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Physics Gurus Come And Help Me Little Sister by Kelly2713(m): 6:31am On Jan 10, 2019
Hi guys, my little sister brought this to me and i decided to bring it here for solution. Thanks as i knw some guys will help
A galvanometer of internal resistance 100 gives a full scale deflection for a current of 10mA. Calculate the values of the resistance necessary to convert the galvanometer to (i) a voltmeter reading up to 5v. (ii) an ameter reading up to 10A
Re: Physics Gurus Come And Help Me Little Sister by fr3do(m): 7:56am On Jan 10, 2019
..

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Re: Physics Gurus Come And Help Me Little Sister by femi4: 8:32am On Jan 10, 2019
Kelly2713:

Hi guys, my little sister brought this to me and i decided to bring it here for solution. Thanks as i knw some guys will help
A galvanometer of internal resistance 100 gives a full scale deflection for a current of 10mA. Calculate the values of the resistance necessary to convert the galvanometer to (i) a voltmeter reading up to 5v. (ii) an ameter reading up to 10A
v=IR
also v= I(r+R)
for the voltage, 5v, when the galvanometer deflects 10mA
v=I(r+R)
5=0.01(100+R)
5=1+0.01R
5-1=0.01R
R=4/0.01
R=400ohms.
in)when ammeter reads 10A
v=IR , 100*0.01 = 1v
R=v/I
remember it will deflect 10mA(0.01A)
10Amps- 0.01Amps=9.99Amps
Pd across = 1v
R=1/9.99
R=0.1ohm

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Re: Physics Gurus Come And Help Me Little Sister by OwoukoUrua(m): 11:13am On Jan 10, 2019
[quote author=femi4 post=74618485]v=IR also v= I(r+R) for the voltage, 5v, when the galvanometer deflects 10mA v=I(r+R) 5=0.01(100+R) 5=1+0.01R 5-1=0.01R R=4/0.01 R=400ohms. in)when ammeter reads 10A v=IR , 100*0.01 = 1v R=v/I remember it will deflect 10mA(0.01A) 10Amps- 0.01Amps=9.99Amps Pd across = 1v R=1/9.99 R=0.1ohm[/quote
problem solved

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Re: Physics Gurus Come And Help Me Little Sister by Kelly2713(m): 2:27pm On Jan 10, 2019
femi4:
v=IR
also v= I(r+R)
for the voltage, 5v, when the galvanometer deflects 10mA
v=I(r+R)
5=0.01(100+R)
5=1+0.01R
5-1=0.01R
R=4/0.01
R=400ohms.
in)when ammeter reads 10A
v=IR , 100*0.01 = 1v
R=v/I
remember it will deflect 10mA(0.01A)
10Amps- 0.01Amps=9.99Amps
Pd across = 1v
R=1/9.99
R=0.1ohm

Thanks brother
Re: Physics Gurus Come And Help Me Little Sister by Kelly2713(m): 2:29pm On Jan 10, 2019
fr3do:
..
Thanks bro

1 Like

Re: Physics Gurus Come And Help Me Little Sister by Whobedatte(m): 7:11pm On Jan 10, 2019
Shey na objective or theory ?
Anyway , if na objective , R = qpr

1 Like

Re: Physics Gurus Come And Help Me Little Sister by Kelly2713(m): 8:53pm On Jan 13, 2019
Whobedatte:
Shey na objective or theory ?
Anyway , if na objective , R = qpr
Lolz
Re: Physics Gurus Come And Help Me Little Sister by Kelly2713(m): 8:54pm On Jan 13, 2019
[quote author=OwoukoUrua post=74623724][/quote]
Yap, thanks

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