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[b][/b]change Of Subject Formular - Education - Nairaland

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[b][/b]change Of Subject Formular by preyeamaorutobi(m): 3:12pm On Feb 03, 2019
Please my fellow nairalanders I need a solving on this question
Make a the subject of the formular

a/x+b/y=a/y

The answer at the back of the text is

a=bxy/xy-y^2
Re: [b][/b]change Of Subject Formular by Shallum(m): 4:05pm On Feb 03, 2019
I need help in calculation of the first order of reaction. Am ask to find the final conc. And my final ans is
LogAt=0.00356
pls how can i find At?
Re: [b][/b]change Of Subject Formular by Kaylhey20: 4:23pm On Feb 03, 2019
preyeamaorutobi:
Please my fellow nairalanders I need a solving on this question
Make a the subject of the formular

a/x+b/y=a/y

The answer at the back of the text is

a=bxy/xy-y^2

a/y -a/x = b/y
ay - ax)

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Re: [b][/b]change Of Subject Formular by Kaylhey20: 4:25pm On Feb 03, 2019
preyeamaorutobi:
Please my fellow nairalanders I need a solving on this question
Make a the subject of the formular

a/x+b/y=a/y

The answer at the back of the text is

a=bxy/xy-y^2

a/y -a/x = b/y
(ay - ax)/xy = b/y
a(y - x)/xy = b/y
Cross multiply
ay(y - x) = bxy

a = bxy/y(y - x)

2 Likes

Re: [b][/b]change Of Subject Formular by Kaylhey20: 4:29pm On Feb 03, 2019
Shallum:
I need help in calculation of the first order of reaction. Am ask to find the final conc. And my final ans is
LogAt=0.00356
pls how can i find At?

If the base of the log is 10, then
Log 10 (At) = 0.00356
At = 10 ^0.00356
Re: [b][/b]change Of Subject Formular by preyeamaorutobi(m): 8:28pm On Feb 03, 2019
Kaylhey20:


a/y -a/x = b/y
(ay - ax)/xy = b/y
a(y - x)/xy = b/y
Cross multiply
ay(y - x) = bxy

a = bxy/y(y - x)
. THANKS BABA I REALLY APPRECIATE WOULD LUV 2GET UR WHATSAPP DIGIT

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