To all lovers of shape
another shape thing to play with.
I am the only African
and the only black moderator in maths quiz
I can relate.
Carry on moderators we are playing in the back yard.

Anyone?

R = 85/6 = 14.166666666.... units.

Cc. Ifada123

ifada123:
Anyone?

R=85/6 or 14.1666666...
SOLUTION:

The dashed lines were added by me.
I drew an imaginary Diameter BD(from the uploaded pix).
BD subtends an angle of 90 deg with C(at the circumference) implies |BC|^2+ |CD|^2= |BD|^2..... Eqn 1
|BC|^2= 8sq + 15sq = 64+225 = 289 or |BC|=17
Now angle BCX+ angle DCY=90
and 15/17=sin BCX =sin(90-DCY)= cos DCY..... Eqn 2
From Triangle CDY |CY|/|CD|= (8+12)/|CD|= 20/|CD|= cos DCY. Putting in eqn 2
15/17 = 20/CD or CD= 68/3
Fron eqn 1 BC=17 and 17^2+(68/3)^2= BD^2.
Or BD^2= 7225/9 or BD=85/3
Therefore R=BD/2=85/6= 14.1666666666.......

Squillaci:


R=85/6 or 14.1666666...
SOLUTION:

The dashed lines were added by me.
I drew an imaginary Diameter BD(from the uploaded pix).
BD subtends an angle of 90 deg with C(at the circumference) implies |BC|^2+ |CD|^2= |BD|^2..... Eqn 1
|BC|^2= 8sq + 15sq = 64+225 = 289 or |BC|=17
Now angle BCX+ angle DCY=90
and 15/17=sin BCX =sin(90-DCY)= cos DCY..... Eqn 2
From Triangle CDY |CY|/|CD|= (8+12)/|CD|= 20/|CD|= cos DCY. Putting in eqn 2
15/17 = 20/CD or CD= 68/3
Fron eqn 1 BC=17 and 17^2+(68/3)^2= BD^2.
Or BD^2= 7225/9 or BD=85/3
Therefore R=BD/2=85/6= 14.1666666666.......

Well explained ...Good job

Good job guys,
The moderator changed the topic and ban me,
I never knew typing moderator is against niaraland rule, enjoy!
I know you don't hate me but what is the cause of the disagreement between us is that I love what you hate "maths"
Besides your topic is boring!.
Anyways I just tested our efficient my trap is

.