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Mathematicians In The House,solve This Permutation Problem - Education - Nairaland

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Mathematicians In The House,solve This Permutation Problem by sunnychibs(m): 11:30am On Jul 22, 2019
in how many ways can 6 colored chalks be arranged if 2 are of the same color?

Show working
Re: Mathematicians In The House,solve This Permutation Problem by Inspectorsuga22(m): 11:37am On Jul 22, 2019
Uncle I'm not seeing well n my biro is not writing well too... When I come tomorrow I will copy the correction... grin grin tongue tongue

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Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 12:33pm On Jul 22, 2019
AABCDE
6!/(2!)=sum of angles at a point.

Explanation 6 chalks can be arranged in 6! Ways
So we will divide by the how many way each of the identical item can be arranged
Identical here is AA it can be arranged in 2! ways
Thus
=6!/2!=6×5x4x3=360ways
@sunnychibs

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Re: Mathematicians In The House,solve This Permutation Problem by Martinez39(m): 9:13pm On Jul 22, 2019
sunnychibs:
in how many ways can 6 colored chalks be arranged if 2 are of the same color?


Show working
6! ÷ 2! = 360 ways
Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 12:40am On Jul 23, 2019
This question is quite vague.

It is not even clear whether the two monochromatic chalks are to be always placed together or not. The possible answers are 5!/2 and 6!/2 according as whether the monochromatic chalks are to be or not to be placed together.
Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 6:13am On Jul 23, 2019
MathsEconomics:
This question is quite vague.

It is not even clear whether the two monochromatic chalks are to be always placed together or not. The possible answers are 5!/2 and 6!/2 according as whether the monochromatic chalks are to be or not to be placed together.
Yes broda its not complete
Re: Mathematicians In The House,solve This Permutation Problem by Olorunnim: 10:13am On Jul 23, 2019
Uncle my biro haf finish
Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 11:28am On Jul 23, 2019
MathsEconomics:
This question is quite vague.

It is not even clear whether the two monochromatic chalks are to be always placed together or not. The possible answers are 5!/2 and 6!/2 according as whether the monochromatic chalks are to be or not to be placed together.
It is clear, when no condition is attached
You do it for they can be placed or they can't be placed together. The question is very correct.
Re: Mathematicians In The House,solve This Permutation Problem by Gorioye: 3:58pm On Jul 23, 2019
6!/2!2! 6x5x4x3x2x1/2x1x2x1
6x5x4x3/2x1 360/2 = 180 Q.E.D.
Re: Mathematicians In The House,solve This Permutation Problem by CodeTemplar: 5:46pm On Jul 23, 2019
360
Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 6:42pm On Jul 23, 2019
Gorioye:
6!/2!2! 6x5x4x3x2x1/2x1x2x1

6x5x4x3/2x1 360/2 = 180 Q.E.D.
Note correct

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