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Hardest Maths Question by Rasulullah: 2:21pm On Nov 09, 2010 |
Hey guys this question was given in question 1,essay part, 2009 FINAL COWBELL NASSMAC COMPETITION LAGOS, please we seriously need help on it.(the numbers after the letters are powers) x+y+z=1 x2+y2+z2=34 x3+y3+z3=97
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Re: Hardest Maths Question by Rasulullah: 3:24pm On Nov 09, 2010 |
A |
Re: Hardest Maths Question by EMMYD01(m): 8:56pm On Nov 09, 2010 |
Raise to power what,is it power 2. I mean d numbers attached to alphabets |
Re: Hardest Maths Question by ccollins(m): 9:01pm On Nov 09, 2010 |
Xd |
Re: Hardest Maths Question by Nobody: 9:43pm On Nov 09, 2010 |
^^ answer it now, mr UNN |
Re: Hardest Maths Question by Nobody: 9:45pm On Nov 09, 2010 |
@op, what is the question or what are we to do? Are we to find the value of the variables? |
Re: Hardest Maths Question by Rasulullah: 9:35am On Nov 10, 2010 |
You are required to find x, y, z |
Re: Hardest Maths Question by Nobody: 2:50pm On Nov 10, 2010 |
Will simultaneous equation or matrix solve the question? |
Re: Hardest Maths Question by bforce(m): 3:01pm On Nov 10, 2010 |
nither simultaenous nor matrix can, i fink it has to do with smtn higher |
Re: Hardest Maths Question by Rasulullah: 3:32pm On Nov 10, 2010 |
Matrix wil not solve it because all d coefficients are zero |
Re: Hardest Maths Question by EMMYD01(m): 3:49pm On Nov 10, 2010 |
I'll get back here in d evening cos presently am in d vehicle 4rm ibadan to lag. When i get home,i'll try it |
Re: Hardest Maths Question by Rasulullah: 3:55pm On Nov 10, 2010 |
Safe journey |
Re: Hardest Maths Question by Rasulullah: 5:21pm On Nov 10, 2010 |
I think it wil not b solve using substitution method, rather using coeffitients does not come here |
Re: Hardest Maths Question by segunanis: 12:37pm On Nov 11, 2010 |
Complex solutions Complex solutions |
Re: Hardest Maths Question by Nobody: 12:35am On Nov 12, 2010 |
No mathematician in the house? |
Re: Hardest Maths Question by Odirah(m): 12:39am On Nov 12, 2010 |
D question wil be solved using a subtitution method,its a simultaneous equation with 3 variables. |
Re: Hardest Maths Question by bforce(m): 6:35am On Nov 12, 2010 |
if u re gonna use substitution its gona be very complex nd out of control cos i tried it, anyway still du wat u cn cos i really wnt tu know the answer |
Re: Hardest Maths Question by abioila(m): 7:42am On Nov 12, 2010 |
Hold on guys.i tink i shuld b able to solve it. |
Re: Hardest Maths Question by EMMYD01(m): 8:09am On Nov 12, 2010 |
Guys,i don't think d question is right because its a simultaneous linear equation with three unknowns and the step i took is take a pair of d equation and eliminate one of d variables and later take another pair ,then bring together what u got 4rm d first and second pairing and then solve it like simultaneous equation. Then finally substitute these values in one of d origina equation to obtain d third value. But i've been solving other question like this but in this one now the varibles are giving me zero. Mayb its not correct. |
Re: Hardest Maths Question by Rasulullah: 8:58am On Nov 12, 2010 |
D question is 100% correct |
Re: Hardest Maths Question by Seun(m): 8:59am On Nov 12, 2010 |
The 3rd equation is probably wrong. |
Re: Hardest Maths Question by Rasulullah: 9:00am On Nov 12, 2010 |
I wonder why dey gave us dat question last year, at 14 yrs |
Re: Hardest Maths Question by Rasulullah: 9:06am On Nov 12, 2010 |
I hv d answers, but my problems are d steps and solutions, I GOT D ANSWER FROM MICROSOFT MATHS, but i think it uses graphical method with 3d, I NEED UR PERMISSIONS TO PASTE D ANSWER, but help me take to a lecturer or prof |
Re: Hardest Maths Question by abioila(m): 9:06am On Nov 12, 2010 |
Mehn dis work na die.but am vry sure its GUSSIAN rule that one can use 2 solve it,i.e makn one of d variables subjet of formla in one of d 3 equations nd pairn 2 of d oda 3 equations,substn d value of the changd subject of formla in those equatns then solvin simultaneously.afta dat replace d values of the variables in any of d 3 initial equatns to get ur answa.but as pa dis work d fuda u go d more complicatd d solutn.and dis was d first tin i did today on d bed,now am avn serious headache. |
Re: Hardest Maths Question by Nobody: 9:18am On Nov 12, 2010 |
Oga maths oo |
Re: Hardest Maths Question by Tunsbobo(m): 9:41am On Nov 12, 2010 |
Omo, i tried using 3X3 matrix, but my answer wasn't correct! I don't know how to answer this question, i also tried substitution method but the question just became more complex. |
Re: Hardest Maths Question by abioila(m): 10:59am On Nov 12, 2010 |
U cant use matrix because 4rm what I noe u can only use matrix to solve linear simultaneous equatns but dis one is not linear. |
Re: Hardest Maths Question by Semitexy: 11:10am On Nov 12, 2010 |
dont provide the answer yet because to every pro there is always a solution |
Re: Hardest Maths Question by Nobody: 12:07pm On Nov 12, 2010 |
@topic im almost there |
Re: Hardest Maths Question by Rasulullah: 1:08pm On Nov 12, 2010 |
[h3]I am alwayz saying dis, MATRIX wil not solve dis because d coefficients are all d same(=1) [/h3] 1 Like |
Re: Hardest Maths Question by Ymodulus: 3:56pm On Nov 12, 2010 |
Mehn dis work na die.but am vry sure its GUSSIAN rule that one can use 2 solve it,i.e makn one of d variables subjet of formla in one of d 3 equations nd pairn 2 of d oda 3 equations,substn d value of the changd subject of formla in those equatns then solvin simultaneously.afta dat replace d values of the variables in any of d 3 initial equatns to get your answa.but as pa dis work d fuda u go d more complicatd d solutn.and dis was d first tin i did today on d bed,now am avn serious headache.stories work am guy |
Re: Hardest Maths Question by Nobody: 4:54pm On Nov 12, 2010 |
^ why are you looking for trouble here and there? |
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