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Please Help Solve This Mathematical Question by bolshoiboo: 3:42pm On Oct 29, 2011 |
please can anyone solve this question and show workings. (i/5)-((2-2i)/(4-3i)). Thank you |
Re: Please Help Solve This Mathematical Question by Afam4eva(m): 4:07pm On Oct 29, 2011 |
Which kind maths question be this? |
Re: Please Help Solve This Mathematical Question by bolshoiboo: 4:11pm On Oct 29, 2011 |
it's a complex number question |
Re: Please Help Solve This Mathematical Question by Afam4eva(m): 4:13pm On Oct 29, 2011 |
what's 2-2i? |
Re: Please Help Solve This Mathematical Question by bolshoiboo: 4:22pm On Oct 29, 2011 |
it's a complex number, 2 is the real part while 2i is the imaginary part. Have you any idea of what a complex number is? |
Re: Please Help Solve This Mathematical Question by Afam4eva(m): 4:24pm On Oct 29, 2011 |
Re: Please Help Solve This Mathematical Question by bolshoiboo: 4:29pm On Oct 29, 2011 |
thank you, I'll check it. I hope it helps! |
Re: Please Help Solve This Mathematical Question by Ogbeozioma: 7:05pm On Oct 29, 2011 |
Not sure if its correct but i got (9+6i)(15i-20) where i= sqrt of -1 |
Re: Please Help Solve This Mathematical Question by Ogbeozioma: 7:09pm On Oct 29, 2011 |
I meant (9+6i)/(15i-20) |
Re: Please Help Solve This Mathematical Question by Sammy107d(m): 7:26pm On Oct 29, 2011 |
Ok, I do finance not maths, so this can be ridden with errors. Also typed on my phone so ignore the capitalization of 'I'. I/5 - ((2-2i)/4-3i)) = 0 I/5 = (2-2i)/(4-3i) I/5(4-3i) = (2-2i) I(4-3i)/5 = (2-2i) I(4-3i) = 5 (2-2i) 4i - 3i^2 = 10 - 10i 4i - 3i^2 + 10i = 10 -3i^2 + 14i - 10 = 0 Using almighty formula (-b±*sq root of* b^2-4ac/2a) -14 ± *sq root of* -14^2 - 4 (-3*-10)/2*-3 -14 ± *sq root of* 196 - 120/-6 -14 ± 8.72 / -6 -14 ± -1.45 I = -14 - 1.45 or I = -14 + 1.45 I = -15.45 or I = -12.55 I doubt this is correct, probably because the quadratic cannot be solved by factorization. But at least this is one attempt. Hopefully the correct answer can be found if you guys correct whatever errors you find. |
Re: Please Help Solve This Mathematical Question by Ogbeozioma: 7:50pm On Oct 29, 2011 |
Sammy107_d:bros sorry but this is complex number not ordinary algebra. What u see as "i" is not actually 'i'. "I" is sqrt of -1. Since it doesnt have any mathematical value, mathematicians and engineers decided call it "i" or "j". So it is not a variable,its a constant. |
Re: Please Help Solve This Mathematical Question by Sammy107d(m): 7:59pm On Oct 29, 2011 |
Oh ok. That's interesting to learn. Not all letters are random like 'x'. Thanks |
Re: Please Help Solve This Mathematical Question by bolshoiboo: 8:01pm On Oct 29, 2011 |
Thanks to you all for your replies, I have been able to solve it. The answer is -14/25+7/25i |
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