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Nairaland Forum / Nairaland / General / Education / Someone Should Pls Help Me Out (878 Views)
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Someone Should Pls Help Me Out by Gbengaslc: 9:53am On Apr 30, 2012 |
Hi great nls Pls help me out of this question.Pls i need explanation and tips on how to solve similar question.the question goes thus: . Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one. A. 12 sec B. 24 sec C. 48 sec D. 60 sec |
Re: Someone Should Pls Help Me Out by TheArbiter: 10:14am On May 03, 2012 |
Your question is structured incorrectly. You need to clarify one issue. Take a look at the representations of the problem below. The letter D represents the train driver. Which of the configuration below best describes your question? DCCCCCCCCCCCCCCCCCCCCCC Fast train ---> <--- DCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC Slow train Configuration A. DCCCCCCCCCCCCCCCCCCCCCC Fast train ---> <---- CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCD Slow train Configuration B. |
Re: Someone Should Pls Help Me Out by TheArbiter: 10:44am On May 03, 2012 |
Took the liberty of solving without waiting for your input since it was not very difficult. For configuration A, the answer is 24secs. For configuration B, the answer is 48secs. Solution Logic: In a time t, slow train travels x meters. In a similar time period fast train travels (500-x) meters and (1000-x) meters respectively for configurations A and B. Using your physics equation: S= Ut + (1/2at2). Terms in brackets = 0 since no acceleration. Hence: slow train: x=30t fast train: (500-x)=45t or (1000-x)=45t depending on configuration. Substitute for x and solve. Dont forget to get your units right. |
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