ositadima1:

I owe you then..., again thnx man.

You owe me nothing man. Watch out for more questions

ositadima1:

07065104668

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ositadima1:

Can u PM my spoils, Mtn would be nice

How can I PM you? I tried going to your profile and clicked to send email but the page that came up only showed a prepared and uneditable message.

ositadima1:

The scalar Q=xyz
grad=(d/dx, d/dy, d/dz)

Where d/dx, d/dy, d/dz are partial derivatives

grad(xyz)=[d(xyz)/dx, d(xyz)/dy, d(xyz)/dz]

grad(xyz)=[yz, xz, xy]

We now have a vector...[yz, xz, xy]

curl[yz, xz, xy]= grad x [yz, xz, xy]

where x is a vector cross

curl[yz, xz, xy]= [d/dx, d/dy, d/dz] x [yz, xz, xy]
Matrix form for d curl

curl[yz, xz, xy]=
| i j k |
|d/dx d/dy d/dz|
| yz xz xy |
Breaking down d matrix...

curl[yz, xz, xy]= [d(xy)/dy-d(xz)/dz]i-[d(xy)/dx-d(yz)/dz]j+[d(xz)/dx-d(yz)/dy]k

curl[yz, xz, xy]=[(x-x)i-(y-y)j+(z-z)k]

curl[yz, xz, xy]=[(0)i-(0)j+(0)k]

curl[yz, xz, xy]=[0]=0

This is outstanding! Lemme have your phone number

1000 naira GLO recharge card for anyone who can prove the below mathematical expression.

Given that Q = xyz
Prove that the CURL of GRAD Q = 0