Oxide65:

Sire, does this correspond with your result?

maybe....

workings will be cool bruv.


BTW: Am not a sir ooo

benbuks:

maybe....

workings will be cool bruv.


BTW: Am not a sir ooo

OK I tot u had d result already. Lemme sharply arrange d working.

Oxide65:

OK I tot u had d result already. Lemme sharply arrange d working.

ok prof.

anticipating .

benbuks:

maybe....

workings will be cool bruv.


BTW: Am not a sir ooo

I Hope it's clear enough. I prefer writing to typing. Please just manage it.

Oxide65:

I Hope it's clear enough. I prefer writing to typing. Please just manage it.

hmmm..

in fact..

Integrate arctan([(1-x)/(1+x)]dx

asap.

If vector p=i+2j-2k and q=2i-j+2k.
Find two vectors m and n,such that m is perpendicular to p and n parallel to p.

benbuks: Integrate arctan([(1-x)/(1+x)]dx

asap.

Oboi, give me some hint I'm kinda stuck here.

benbuks: Integrate arctan([(1-x)/(1+x)]dx

asap.

Oboi, please give me some hint I'm kinda stuck here. Thanks.

benbuks:

ok..


$5/x² dx = $5x^-2dx


=> 5 $x^-2 dx = -5x^-1 + k

= -5/x + k

known that integration is the anti. of differentiation

sec x = 1/cosx using quotient rule


(vu' - uv ' )/v²

put 1= u u'= 0
& cosx =v v'=-sinx

say f(x) = secx

we thus have

f '( x) = [0 -(-sinx) ]/ cos²x

=> 1/cosx * sinx/cosx

hence we have secx.tanx ..................( as expected )

thanks a lot sir...ℓ̊ jst learnt sth intersting....in d first qst U̶̲̥̅̊ got -5/x..d integral of it is -5inx right?

benbuks: Integrate arctan([(1-x)/(1+x)]dx

asap.

§tan^-1{(1-x)/(1+x)}dx.
:::SOLUTION:::
Integrating by part, we have;
u=tan^-1{(1-x)/(1+x)}, v=x, dx=-du(1+x²),
§udv=uv-§vdu,
=tan^-1{(1-x)/(1+x)}.x-§-x/(1+x²)dx.
=xtan^-1{(1-x)/(1+x)}+§x/(1+x²)dx.
For §x/(1+x²)dx, we say, let u=x², dx=du/2x. Substituing, we have;
(1/2)§1/(u+1)du.
1/2ln(u+1)+c, recall, u=x².
=1/2ln(x²+1)+c.
.^.. => xtan^-1{(1-x)/(1+x)} + 1/2ln(x²+1) + c.

Arithmetic:
§tan^-1{(1-x)/(1+x)}dx.
:::SOLUTION:::
Integrating by part, we have;
u=tan^-1{(1-x)/(1+x)}, v=x, dx=-du(1+x²),
§udv=uv-§vdu,
=tan^-1{(1-x)/(1+x)}.x-§-x/(1+x²)dx.
=xtan^-1{(1-x)/(1+x)}+§x/(1+x²)dx.
For §x/(1+x²)dx, we say, let u=x², dx=du/2x. Substituing, we have;
(1/2)§1/(u+1)du.
1/2ln(u+1)+c, recall, u=x².
=1/2ln(x²+1)+c.
.^.. => xtan^-1{(1-x)/(1+x)} + 1/2ln(x²+1) + c.

.




Lol very easy but hard to see it's by part. That's y I called u sire. Thanks man. Please send me another lemme try.

compute the anti-derivative of


i) x³ √(1-x² )


ii) [sin(1/cotx) ]/ (1-sin²x )

iii) sin⁷ x

wrt. x

asap.

ugonna1054: thanks a lot sir...ℓ̊ jst learnt sth intersting....in d first qst U̶̲̥̅̊ got -5/x..d integral of it is -5inx right?

yea.. plus an arbitrary constant say 'C' or 'K'

Oxide65: .




Lol very easy but hard to see it's by part. That's y I called u sire. Thanks man. Please send me another lemme try.

yea man. that's Arithmetic's solution .



i respect the guy.. integrals could be bloody & complex ..


questions that looks innocent ain't really so in reality , while others that looks complex gat the simplest solution & answer , just need high mathematical strengths & cleverness to decipher . .

benbuks:

yea.. plus an arbitrary constant say 'C' or 'K'

ok..thanks a lot... ℓ̊ wud be taking a course "Mat102" (CALCULUS) dis semester..wud U̶̲̥̅̊ be kind enough to recommend a very good t.book on calculus for my level (100 lev)...thanks.

ugonna1054: ok..thanks a lot... ℓ̊ wud be taking a course "Mat102" (CALCULUS) dis semester..wud U̶̲̥̅̊ be kind enough to recommend a very good t.book on calculus for my level (100 lev)...thanks.

further mathematics project 2 & 3

Engineering maths ... K.A. Stroud or by H.k dass


Additional mathematics


pure mathematics for advanced level by bounday


college mathematics . vol. 2


advanced level mathematics ( pure and applied )


introductory university mathematics 2


business mathematics .


& host of others gat lot of them .



but for beginners use further math project 2 ( contains just differentiation ) , project 3 ( contains just integration ) & engineering mathematics by K.A Stroud ....

hope it helps

benbuks:

further mathematics project 2 & 3

Engineering maths ... K.A. Stroud or by H.k dass


Additional mathematics


pure mathematics for advanced level by bounday


college mathematics . vol. 2


advanced level mathematics ( pure and applied )


introductory university mathematics 2


business mathematics .


& host of others gat lot of them .



but for beginners use further math project 2 ( contains just differentiation ) , project 3 ( contains just integration ) & engineering mathematics by K.A Stroud ....

hope it helps

thanks a bunch.....ℓ̊'ll try them......

Can someone please list professional courses open to a Mathematics graduate/undergraduate.
Thank you in antipation of your favourable response(s).

thankyouJesus: Can someone please list professional courses open to a Mathematics graduate/undergraduate.
Thank you in antipation of your favourable response(s).

Ask google nah

smurfy:

Here goes...

OP = x cm and chord PQ = x cm. Let OM be the line which bisects angle POQ and perpendicularly bisect chord PQ, meeting PQ at M.

It follows that PM = 1/2 * x (or 0.5x), since PQ = x and PM is half PQ.

So, the sine of angle POM = 0.5x/x = 0.5
Hence, angle POM = 30 degrees. So, angle formed by minor sector POQ = 2 * 30 degrees = 60 degrees.
Note that angle POQ = 2 * angle POM.

Hence, angle formed by major sector POQ = 360 - 60 = 300 degrees.

thanks bro.. Sorry for replying late..
Thanks man

Please what is the formular for calculating percentage error

Is this Mathematics or Arithmetic?

Pls wat happened here..where is everybody??

Ok..lemme drop a question here;

Q: what is the gamma function of 1/2?

please differentiate 5^(-3x)

Elliotwiz1: please differentiate 5^(-3x)

let y=5^-3x

using say d (a^x ) /dx = a^x Ina ........( from standard derivative )

now put -3x= u

=> -3=du/dx

=> y=5^u

dy/du =5^u In5

dy/dx = du/dx * dy/du

=> (-3)(5^u.In5 )

since u=-3x

we thus have

-3(5^-3x.In5) …

hope you get...?

Mozarinia: Is this Mathematics or Arithmetic?

which do you think ..?

integrate √(x^2 - 1) dx ..

dejt4u: Pls wat happened here..where is everybody??

Ok..lemme drop a question here;

Q: what is the gamma function of 1/2?

= √pi.


sch. tinz bro.....


no much tym...

Kovic08: Please what is the formular for calculating percentage error

(estimated error - real error )/real error * 100