Videx1:
agentofchange is that all about moment generating function

agentofchange1:
@ factorial1 u try sir ,
differential calculus is quite cheep , but even though integral calculus is the reverse of it , its not usually funny to do so . Now in this regards , how can we then obtain back the integrand .?

jackpot:
i use to tell the junior ones that it is easier to destroy a house than to build. Same way it's easier to differentiate than to integrate.

Cymbal:
Kindly help me with this.
..."Prove that the equation R=COS@ represent equation of a circle"...
TAGS: agentofchange1 ,jackpot,benbuk,laplacian,dejt4u, and evry math guru. THANKS.

Cymbal:
Kindly help me with this.
..."Prove that the equation R=COS@ represent equation of a circle"...
TAGS: agentofchange1 ,jackpot,benbuk,laplacian,dejt4u, and evry math guru. THANKS.

Cymbal:
Kindly help me with this.
..."Prove that the equation R=COS@ represent equation of a circle"...
TAGS: agentofchange1 ,jackpot,benbuk,laplacian,dejt4u, and evry math guru. THANKS.

agentofchange1:
How will I go about this plz..?.
The function f(x,y) satisfies
1) f(0,y)=y+1
2)f(x+1,0)=f(x,1)
3)f(x+1,y+1)=f(x,f(x+1,y)) for all non negative integers x,y.
determine f(4,1981)

jackpot:
google functional equations

Cymbal:
Find in what ratio the points; (4b-2a , 9c-a) divides the line joining the points (a+b , 3c+5a) and (5b-3a , 11c-3a).

agentofchange1:


3:1

Cymbal:
kindly show the workings!

Nature130:
Help me with these questions ; find the values of x and y in ; x^y+y^x=17 and x+y=5. (2) find the value of x in 4^x=8x.

jackpot:
r= cos@= x/r implies
r²=x implies r²-x=0 implies
x²-x+y²=0 implies
(x- ¹/₂)²+(y-0)²= (¹/₂)²

This is an equation of circle centred at (¹/₂, 0) with radius ¹/₂.

jackpot:
question 3

a military jet bomber flying at an altitude 600m in a horizontal straight line above a target with a speed of 360km/h drops off a bomb in order to hit the target with an initial velocity 0km/h. Suppose that at the time of drop, the horizontal distance of the target from the jet is 750m and the bomb's explosion radius is 300m, determine whether the target is hit by the bomb. If not, what is the range of the miss?

Laplacian:

x^y+y^x=17 and x+y=5, using modular arithmetic, and letting # denote "congruent to" we have;
x^y # 17 (mod y) and
x # 5 (mod y)
hence; 5^y # 17 (mod y). Since y is relatively prime to 5 and 17, we have, by Fermat's Little Theorem,
5^y # 5 # 17 (mod y), hence, 12 # 0 (mod y), so y is a positive divisor of 12 and is less than 5, the only candidate are
y= 2 or 3 or 4, same argument goes for x since the equation is symetrical. So,
x= 2, or 3, or 4 and
y=2, or 3, or 4.
Suppose x<y, then, 2x<x+y=5 hence x<2.5. If x is less than x then x=2 and hence, from y=5-x, y=3

agentofchange1:


nice try sir, av known of this method too but the problem is , its still an approximate, since we truncate @ the 3rd term of expansion , why not 4th or 5th or higher ?. that's because we already know the answer to be 2 by trial -by-error , which is not always the ideal way of solving mathematical problems .


Now can it work for this ?

4^x = x^4 .?

or 3x = 8^x

jackpot:
another angle of attack, that's cool

Laplacian:

x⁴=4^x
first; (x⁴)^1/x=4, since the RHS is an integer, x must divide 4;
similarly;
x=(4^x)^1/4, again since LHS is an integer, 4 must divide x.
Hence, if x divides 4 and 4 divide x, then x=4.

For; 3x=8^x, since 3 cannot divide 8, no integer x can satisfy that equation

agentofchange1:


x=(pX2+qX1)/(p+q)

y=(pY2+qY1)/(p+q)
Where x,y={(4b-2a),(9c-a)}
X1,Y1={(a+b),(3c+5a)}

X2,Y2={(5b-3a),(11c-3a)}
4b-2a={(5b-3a)p+(a+b)q}/(p+q)

P(a-b)=3q(a-b)
P=3q
hence
p:q=3:1

Nature130:
Help me with these questions ; find the values of x and y in ; x^y+y^x=17 and x+y=5. (2) find the value of x in 4^x=8x.

Cymbal:
Help me with this : Find the equation of the circle which touches the axis of y at a distance +4 from the origin and cuts off an intercept 6 from the axis of x.
TAGS: agentofchange1 ,jackpot,laplacian.

Laplacian:

at least three points are required to specify a circle, so we must determine the second intercept on the x-axis; if the second intercept is k, then; k=4²/6=8/3
so the three points are; (0,4), (6,0), (8/3,0). Hope it helps!!

agentofchange1:
How will I go about this plz..?.
The function f(x,y) satisfies
1) f(0,y)=y+1
2)f(x+1,0)=f(x,1)
3)f(x+1,y+1)=f(x,f(x+1,y)) for all non negative integers x,y.
determine f(4,1981)

Cymbal:
it helps buh please kindly give me full solution and explain how k=8/3.THANKS.

Laplacian:

heard of Newton's theorem for the radius of curvature of a line?

Cymbal:
nah

Laplacian:


ok. Just google "intersecting arc theorem" because i can't draw the diagram here