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Re: Nairaland Mathematics Clinic by DatechMan(m): 8:28am On Jan 28, 2016 |
dprinz99: Correct the questions if I'm mistaken. 1. 1/8 * 7-3 = y3 2-3 * 7-3 = y3 (2*7)-3 = (1/y)-3 2*7 = 1/y y = 1/14 2. (√5 -2)2 - z = (1 - √20)2 z = (√5 -2)2 - (1 - √20)2 z = 5 - 4√5 + 4 - 1 + 2√20 - 20 z = -12 - 4√5 + 2√20 z = -12 - 4√5 + 4√5 z = -12 1 Like |
Re: Nairaland Mathematics Clinic by Nobody: 8:18pm On Jan 28, 2016 |
somebody in the house should please help me expand (x + 4)^3 and (x + 2)^4 Bionomially please guys its urgent. thanks |
Re: Nairaland Mathematics Clinic by DatechMan(m): 9:28pm On Jan 28, 2016 |
youngdude1: Bionically?? I guess you mean Binomially? Lol |
Re: Nairaland Mathematics Clinic by Nobody: 9:37pm On Jan 28, 2016 |
DatechMan:YES..that was a typo *modified* |
Re: Nairaland Mathematics Clinic by thankyouJesus(m): 9:45pm On Jan 28, 2016 |
youngdude1:use Pascal's triangle or Combination method. Hint: for power 3-----1-3-3-1(Pascal''s triangle method). Opps, low battery. |
Re: Nairaland Mathematics Clinic by Nobody: 9:54pm On Jan 28, 2016 |
thankyouJesus:i don't get you |
Re: Nairaland Mathematics Clinic by DatechMan(m): 10:09pm On Jan 28, 2016 |
youngdude1: (x + 4)3 x3 + 3C1 x2.4 + 3C2 x.42 +33 x3 + 12x2 + 48x + 27 |
Re: Nairaland Mathematics Clinic by benji93: 11:15pm On Jan 28, 2016 |
DatechMan:Thıs observatıon ıs especıally for u is prime where u is the power of exponetial expression for which the total number of digits are to be found, try 3^129, 3^17 though logk<1 but there are cases where logk is very close to 1, thus altering the actual approximation of the number of digits |
Re: Nairaland Mathematics Clinic by Nobody: 11:42pm On Jan 28, 2016 |
DatechMan:is that C or a bracket? Thanks |
Re: Nairaland Mathematics Clinic by ElDeeVee(m): 5:03am On Jan 29, 2016 |
youngdude1:C is Combination. |
Re: Nairaland Mathematics Clinic by DatechMan(m): 7:36am On Jan 29, 2016 |
benji93:Yes, I must admit there are cases where it is extremely close. But I don't think there exist a situation where it is actually 1. There's an exception though. When the index is 1. e.g 1250 For the instances above: 3129 has 62 digits. 129log3 = 61.5486... (Rounded up, we have 62) valid 317 has 9 digits. 17log3 = 8.111... (Rounded up, we have 9) valid Good Morning Nigeria #GodBlessNigeria |
Re: Nairaland Mathematics Clinic by Nobody: 10:39am On Jan 29, 2016 |
ElDeeVee:thanks |
Re: Nairaland Mathematics Clinic by benji93: 12:43pm On Jan 29, 2016 |
DatechMan:Oh isee thts ur idea of rounding up and ofcourse not there is never a case where it is 0.1 or 1 exactly it comes from the idea that it comes from the fact that every exponential expression a^b>1 is such that 10^n-1<a^b>10^n infact it was from this axiom i thought that a^b could be at any point at infinity very close to the lower boundary or the upper boundary, if it is very close to the upper boundary, where logk <1 normally based on your rounding up if you had n=999.62 forexample it would be 1000 but actually if the value of k is to considered you could have 999.62 + 0.4 which gives 1000.02 which should be approximated to 1001 somehow we would not be able to test all numbers to infinity, but we can test as many number of digits as possible, i am not trying to disprove you bro,i am just saying based on my assumption there is a possibilty of having that +-1 problem somewhere at infinity unless my assumption is wrong which is also another possibility, we are in a mathematical world, there are just too many things that are not exactly predictable.All the best |
Re: Nairaland Mathematics Clinic by Agnesgrace(f): 4:09pm On Jan 29, 2016 |
Youngsage:. Please is logx + log y the same as log(x+y) recalling that log2 + log 3 is equal to log(2 x 3) which is not equal to log(2+3) |
Re: Nairaland Mathematics Clinic by Agnesgrace(f): 4:20pm On Jan 29, 2016 |
Wonderful forum...Happy new year to you all. |
Re: Nairaland Mathematics Clinic by DatechMan(m): 10:02pm On Jan 29, 2016 |
Agnesgrace:Same to you dear. About your post about Logx + logy na mistake. The guy dey dream. Welcome on board #GodBlessNigeria |
Re: Nairaland Mathematics Clinic by johnpaul1101(m): 6:29pm On Jan 30, 2016 |
goodevening all, plz i need ya help here: diffferentiate d fllwn; (1).....Y=sqre root(X+X^2) (2)....Y=(3X^4)-(X^-1).
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Re: Nairaland Mathematics Clinic by Agnesgrace(f): 7:10pm On Jan 30, 2016 |
Please somebody should help me with this question it is urgent pls. The third term of a geometric progressiom is nine times the first term.if the second term is one-twenty fourth the fifth term.find the fourth term.ar^2=9a. r=sqr of 9 r=3.pls teach me how to get the first term |
Re: Nairaland Mathematics Clinic by Ajibade105(m): 7:51pm On Jan 30, 2016 |
This thread has made some people to be lazy. People come here to ask questions without extra efforts to get them solved. I think before any question(s) is been solved on this thread. You will need to upload your solved solution and people on this thread will then guide you to solve them. 2 Likes |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 7:53pm On Jan 30, 2016 |
johnpaul1101: (2)....Y=(3X^4)-(X^-1). dy/dx = 12x^3 + x^-2 guess that's it.....hope u get [/quote] |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 7:54pm On Jan 30, 2016 |
Ajibade105: exactly the point sir.. .I just taya..4 dem.... its well sha. 1 Like |
Re: Nairaland Mathematics Clinic by Agnesgrace(f): 8:40pm On Jan 30, 2016 |
Agnesgrace:. Pls much effort hd been made to solve this problem. Only r is obtainable pls if u know the first term help pls |
Re: Nairaland Mathematics Clinic by johnpaul1101(m): 9:14pm On Jan 30, 2016 |
agentofchange1:I was actually hoping u'd do dat using the 2nd-p. |
Re: Nairaland Mathematics Clinic by Ajibade105(m): 9:46pm On Jan 30, 2016 |
Agnesgrace: Find a paper write the question on it, snap n upload it here |
Re: Nairaland Mathematics Clinic by DatechMan(m): 9:49pm On Jan 30, 2016 |
Agnesgrace: You question is seemingly inconsistent. For a G.P the ratio of T5 to T2 is always r3. Therefore I can't figure out why T2 is 1/24 of T5. Kindly double check the question. Is there something I'm missing? Also note that knowing the ratio of terms in GP cannot give us the value of the first term, I think more information are needed |
Re: Nairaland Mathematics Clinic by Agnesgrace(f): 10:03pm On Jan 30, 2016 |
DatechMan:. Thanks very much, that is how the question ís hv checked again and again pl i dont know if there is any other approach |
Re: Nairaland Mathematics Clinic by DatechMan(m): 10:48pm On Jan 30, 2016 |
johnpaul1101: FYI. I had to jump some steps. Hope the algorithm is clear
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Re: Nairaland Mathematics Clinic by Agnesgrace(f): 11:25pm On Jan 30, 2016 |
Agnesgrace:Thanks very much great people i hd done justice to that. Have a wonderful night rest. Bye 1 Like |
Re: Nairaland Mathematics Clinic by DatechMan(m): 7:20am On Jan 31, 2016 |
Agnesgrace: Would you be kind enough to share with us? |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 9:11am On Jan 31, 2016 |
johnpaul1101:you didn't indicate what's to be used BTW: what's. '2nd-p' ? |
Re: Nairaland Mathematics Clinic by DatechMan(m): 11:19am On Jan 31, 2016 |
agentofchange1: Maybe 2nd-p = Second Principle Please forgive my ignorance. johnpaul1101 kindly shed light |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 1:00pm On Jan 31, 2016 |
DatechMan:lolz. ..haha.. I wanted to say so......just wanted to be sure... .... we learn everyday u kw... #Happy.Sunday. |
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