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Nairaland Forum / Nairaland / General / Education / Nairaland Mathematics Clinic (494068 Views)
Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
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Re: Nairaland Mathematics Clinic by Hadampson(m): 10:05pm On Nov 21, 2016 |
ladokuntlad:pls boss, i cnt see d answer very well. could u type it instead pls |
Re: Nairaland Mathematics Clinic by ladokuntlad(m): 2:12pm On Nov 22, 2016 |
Hadampson: Can't start typing ooo D solution is r=2 a=5 |
Re: Nairaland Mathematics Clinic by Hadampson(m): 10:42am On Nov 24, 2016 |
ladokuntlad:pls boss just tell me how u get d quadratic equation when solving for constant ratio. |
Re: Nairaland Mathematics Clinic by profmathsland(m): 3:48pm On Nov 24, 2016 |
strictlynaija: The first thing you need to do is to obtain the trigonometric identity for sec X. Now sec X=sec X *1=sec x((sec x+tan x) /(sec x +tan x)). At this point you will integrate the simplicities of sec X using the u-substitution which will give you a final result as ln(secx +tanx) +c. 1 Like |
Re: Nairaland Mathematics Clinic by Nobody: 2:16am On Dec 01, 2016 |
What is the curl of A = y i - z2j + (y - x2)k at the point (1,2,1) ? |
Re: Nairaland Mathematics Clinic by Nobody: 4:26am On Dec 01, 2016 |
Teempakguy: curl A = 3i + 2j - k |
Re: Nairaland Mathematics Clinic by Nobody: 3:11pm On Dec 01, 2016 |
Nigayoyo:no working? ![]() |
Re: Nairaland Mathematics Clinic by Nobody: 5:05pm On Dec 01, 2016 |
Teempakguy: curl A = V x A = i [d/dy(y-x^2) + d/dz(z^2)] - j [d/dx(y-x^2)-d/dz(y)] + k [d/dx(-z^2) - d/dy(y)] = (1+2z)i + (2x)j - k Evaluating at (1,2,1) yields: curl A = 3 i + 2 j - k That was a pain in the a** ![]() |
Re: Nairaland Mathematics Clinic by Nobody: 5:31pm On Dec 01, 2016 |
Nigayoyo:haha, sorry about that. I was just trying to compare results. 1 Like |
Re: Nairaland Mathematics Clinic by Oluwatosint(m): 10:08am On Dec 18, 2016 |
Ok |
Re: Nairaland Mathematics Clinic by Umartins1(m): 8:28pm On Dec 27, 2016 |
Oluwatosint:I can't see anything. |
Re: Nairaland Mathematics Clinic by dejt4u(m): 11:33pm On Jan 03, 2017 |
Richiez:If you are an undergraduate, check this thread for a chance to win 50k scholarship this January. Limited space available. https://www.nairaland.com/3551871/annual-xfire-nairaland-undergraduate-quiz |
Re: Nairaland Mathematics Clinic by trino: 9:04am On Jan 04, 2017 |
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Re: Nairaland Mathematics Clinic by trino: 12:48am On Jan 06, 2017 |
mathematicians! This is more interface of the awesome testdriller software
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Re: Nairaland Mathematics Clinic by Kayode7015: 2:43pm On Jan 11, 2017 |
Join ERUDITES OF ERUTION FOR HOT BRAINSTOM IN ALL AREAS OF MATHEMATICS... WHATSAPP LINK: https:///0ifSN65G0rO8xhUEqAVcAv JOIN AND THE FABULOUSLY IMPACTED! |
Re: Nairaland Mathematics Clinic by Edozie82: 9:56am On Jan 20, 2017 |
Good Morning pals and also the admin of this great n amiable forum. Please, how can one define n explain logical reasoning in Mathematics? thanks. |
Re: Nairaland Mathematics Clinic by Nobody: 4:38pm On Feb 13, 2017 |
Someone should please help me with solutions to these questions.
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Re: Nairaland Mathematics Clinic by Nobody: 10:10pm On Feb 15, 2017 |
crouch2014:sorry can't solve it ![]() crouch2014:sorry can't solve it |
Re: Nairaland Mathematics Clinic by hadassaheke(f): 8:58am On Feb 16, 2017 |
Good morning all, Please someone should help me solve this: Express 3x-2<10+x<2+5x in the form a<x<b. Where a and b are both integers. |
Re: Nairaland Mathematics Clinic by Nobody: 2:31pm On Feb 16, 2017 |
Please help
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Re: Nairaland Mathematics Clinic by Ifeshyne(f): 3:03pm On Feb 16, 2017 |
nnamdi1998:So, the man has 24,000 Then he gave his wife ¼ of 24,000 which is 6,000 Then his two sons 2/3 of 24,000 which is 16,000 So total for wife and sons = 6,000+16,000 = 22,000 Amount remaining = 24,000-22,000 = 2,000 Remainder was divided equally among two daughters = 2,000/2 = 1,000 So amount each daughter received = 1,000 I stand to be corrected if wrong though. 2 Likes |
Re: Nairaland Mathematics Clinic by Nobody: 3:09pm On Feb 16, 2017 |
Ifeshyne:Thanks sir,you're very good |
Re: Nairaland Mathematics Clinic by Ifeshyne(f): 5:07pm On Feb 16, 2017 |
nnamdi1998:My pleasure. I'm female though |
Re: Nairaland Mathematics Clinic by Nobody: 6:19pm On Feb 16, 2017 |
crouch2014: Q(1). Using Euler formular.. exp(i x)= cosx +i*sinx; exp(i pi/2)=i; exp(i(pi/2+2 *pi*k))=i; where k is any positive integer. i^i=(exp(i(pi/2+2 *pi*k)))^i=exp((pi/2+2 *pi*k)) which is a real number and infinite since k is infinite. |
Re: Nairaland Mathematics Clinic by Nobody: 6:26pm On Feb 16, 2017 |
crouch2014: Will solve Q(2) when am less busy.. that is one dimensional wave equation with boundary conditions. D-Alembert formula is a solution of the one dimensional wave equation or u can use separation variable technique. |
Re: Nairaland Mathematics Clinic by hadassaheke(f): 8:35pm On Feb 16, 2017 |
hadassaheke:Someone should say something about this please. Thanks! |
Re: Nairaland Mathematics Clinic by killsmith(f): 10:45pm On Feb 16, 2017 |
crouch2014:I remember telling you to apply Duhamel's principle.... |
Re: Nairaland Mathematics Clinic by killsmith(f): 10:55pm On Feb 16, 2017 |
Anybody here wants to talk about real/functional analysis,measure theory,topology ring and field theory?....I'm too lazy for the solving kind of math.... |
Re: Nairaland Mathematics Clinic by Deicide: 1:57pm On Feb 17, 2017 |
hadassaheke:3x-2<10+x<2+5x = 3x-2-10<10-10+x<2-10+5x =3x - 12 < x < -8 + 5x = 6 < X < 2 1 Like |
Re: Nairaland Mathematics Clinic by Nobody: 2:41pm On Feb 17, 2017 |
Deicide: That is problematic. I think you have gotten it the other way round. Cheers! |
Re: Nairaland Mathematics Clinic by Deicide: 3:24pm On Feb 17, 2017 |
masperano:well you can also solve it separately by picking 1) 3x-2<10+x 2) 10+x<2+5x then solve then join the inequality later... |
Re: Nairaland Mathematics Clinic by Nobody: 4:52pm On Feb 17, 2017 |
Deicide: yea I know, I thought you made a slight error since x cannot be greater than 6 (i.e x>6) and at the same time x less than 2( i.e. x<2) you wrote (6 < X < 2). So it should be the other way round... that is 2< x<6. Cheers! |
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