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Re: Do You Have Any Maths Question? Kindly Bring It On by RichyBlacK(m): 12:41am On Sep 28, 2007 |
Eyohimself: The explanation for this is much easier with a diagram. Let G(z) = P(x is less than z). Since the distribution is symmetric about the mean m, then G(m) = P(x < m) = 50%. The statement "68 percent of the distribution lies within one standard deviation d of the mean" means that: G(m+d) - G(m-d) = 68% = P(m-d<x<m+d) So, we are looking for G(m+d) which is also equal to P(x < m+d) But P(x < m+d) = P(x < m) + P(m < x < m+d) = P(x < m) + 0.5*[P(m-d < x < m+d)] due to symmetric nature of distribution about the mean m = G(m) + 0.5*(G(m+d) - G(m-d)) just substituting = 50% + 0.5(68%) = 50% + 34% = 84% (Answer = D) NOTE: there are several other ways of doing this. |
Re: Do You Have Any Maths Question? Kindly Bring It On by LiquidMind(m): 1:07am On Sep 28, 2007 |
Nice maths tread |
Re: Do You Have Any Maths Question? Kindly Bring It On by ADint(m): 10:28am On Sep 29, 2007 |
Eyohimself: Eyohimself, The agent must sell for $199,395(nearest $). Only Ann's gain is made on the initial cost price. To the Agent the current cost price is 170270 + (0.11*170270) = $188,999.70 So, selling price is 188,999.70 + (0.055*188,99.70) = $199,394.68 ($199,395) |
Re: Do You Have Any Maths Question? Kindly Bring It On by Eyohimself(m): 3:31pm On Sep 29, 2007 |
ADint: Thanks for noting that. I made my calculations based on the assumption that they both had gains on the initial cost price which I think is quite possible. Your contribution is welcomed. You based your solution on the assumption that the Agent made the gain on Ann's selling price which from common logic, is more probable. Thanks for the insight. I thought the other way round. |
Re: Do You Have Any Maths Question? Kindly Bring It On by edusegzy(m): 6:04pm On Oct 01, 2007 |
hi every one, i'm happy to see o much going on on this thread.boy i ' have a lot of catching up to do. eyohimself how is your prep.i'm sure you are in top shape. i'm brewing some stuff. Richyblacky you are such a blessing on this thread. |
Re: Do You Have Any Maths Question? Kindly Bring It On by edusegzy(m): 2:41pm On Oct 02, 2007 |
integrating sec x sec x= sec x (sec x +tan x)/(sec x +tan x)=sec2 x+sec x tan x/(sec x +tan x) integerate: ln(sec x +tan x) |
Re: Do You Have Any Maths Question? Kindly Bring It On by jaybee3(m): 3:30pm On Nov 08, 2007 |
There are 2 rooms. One has 3 light switches and the second one has three light bulbs. U can only enter the one with the light bulbs once. How do u deteremine which of the three light switches corresponds to three of the light bulbs in the second room |
Re: Do You Have Any Maths Question? Kindly Bring It On by RichyBlacK(m): 4:12am On Nov 10, 2007 |
jay bee: 1. Go into room with switches 2. Do the following: i. Put the first switch ON, and leave it ON ii. Put the second switch ON, leave it ON for a while, and then switch it OFF iii. Ignore the third switch 3. Go into room with bulbs: i. The bulb that is ON is controlled by the first switch ii. The one that is OFF, but WARM is controlled by the second switch iii. The one that is OFF, but COLD is controlled by the third switch. NB: Some rather obvious assumptions were made. |
Re: Do You Have Any Maths Question? Kindly Bring It On by Ficco(m): 12:35pm On Nov 16, 2007 |
This forum and questions are too hot for me ,am logging out. |
Re: Do You Have Any Maths Question? Kindly Bring It On by RichyBlacK(m): 10:26pm On Jan 03, 2008 |
Eyohimself, Howz life? How did the GRE go? |
Re: Do You Have Any Maths Question? Kindly Bring It On by opiororo1(m): 9:44pm On Jan 05, 2008 |
I love these guys.I which i also could be a mathematics guru as these guys up here.It's Cooooooooooooool! |
Re: Do You Have Any Maths Question? Kindly Bring It On by candylips(m): 12:36pm On Nov 17, 2009 |
Maths geniuses can someone convert this Euler equation x^2y'' (x) - 2xy' (x) + 2y (x) = 4x^3 to a constant coefficeint problem and show that the solution is given by y (x) = Ax + Bx^2 + 2x^3. |
Re: Do You Have Any Maths Question? Kindly Bring It On by candylips(m): 12:40pm On Nov 17, 2009 |
Can someone solve this 2nd order differencial equation y'' = 2y^3 + 8y where y =2 , y' = - 8 when x=π/4 |
Re: Do You Have Any Maths Question? Kindly Bring It On by idamina: 2:30am On Jan 13, 2013 |
Hey..u guys r gr8 On d above question A pair should be black n black or green and green ryt? If there are 5 black and 5 green socks (not pairs) It implies that we have 10 socks which does not form a complete pair. But if we take away 2(a black and a green), we are left with 8.with that we can form a complete pair If we take away 3..there is no way the remainder can form complete pair. NOTE If u take away any number of socks,it shouldnt be considered as part of the complete pair. So on that note I Feel the ans is 2 being the minimum.. Please if u hav anytin contrary please let me understand..tanx |
Re: Do You Have Any Maths Question? Kindly Bring It On by idamina: 2:37am On Jan 13, 2013 |
On d above question A pair should be black n black or green and green ryt? If there are 5 black and 5 green socks (not pairs) It implies that we have 10 socks which does not form a complete pair. But if we take away 2(a black and a green), we are left with 8.with that we can form a complete pair If we take away 3..there is no way the remainder can form complete pair. NOTE If u take away any number of socks,it shouldnt be considered as part of the complete pair. So on that note I Feel the ans is 2 being the minimum.. Please if u hav anytin contrary please let me understand..tan |
Re: Do You Have Any Maths Question? Kindly Bring It On by sportyblinks: 7:23pm On Jan 13, 2013 |
Mke "t" the subject of d formula in dz Newton's 2nd law of motion : s=ut+1/2.at^2 |
Re: Do You Have Any Maths Question? Kindly Bring It On by Zakdamilare: 6:43am On Jan 14, 2013 |
Pls help me 2 solve this questn..prove that cosec2(x) -cot(x)cosec(x)=1 |
Re: Do You Have Any Maths Question? Kindly Bring It On by Zakdamilare: 7:00am On Jan 14, 2013 |
sportyblinks: Mke "t" the subject of d formula in dz Newton's 2nd law of motion : s=ut+1/2.at^2d eqn wil be change when multiply through by 2,.then u wil hv at^2+2ut-2s=0 and compared it wit general equatn of quadratic ax^2+bx+c=0 4rm there ur a=a, b=2u, c= -2s.then solve it by use of formula d ans wil be t= -2u+- squareroot of 4u^2 +8as all divided by 2a., |
Re: Do You Have Any Maths Question? Kindly Bring It On by Nobody: 11:03pm On Feb 21, 2016 |
edusegzy:Hello sir! !!!!!!!! |
Re: Do You Have Any Maths Question? Kindly Bring It On by seuntosyn: 8:26am On Jan 07, 2017 |
kindly solve this, Rationalize √3 / cube rut 5 + cube rut7 |
Re: Do You Have Any Maths Question? Kindly Bring It On by trino: 12:17am On Jan 08, 2017 |
Try the Testdriller Mathsolver..Can solve any mathematics of any kind. Kindly contact me to order for yours Call/whatsapp:08034047666 Email:testdrillersoftwaresolutions@gmail.com
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Re: Do You Have Any Maths Question? Kindly Bring It On by trino: 9:05pm On Jan 08, 2017 |
still on |
Re: Do You Have Any Maths Question? Kindly Bring It On by Nobody: 8:21am On Jan 09, 2017 |
Y I no fit Sabi maths |
Re: Do You Have Any Maths Question? Kindly Bring It On by thankyouJesus(m): 8:46am On Jan 09, 2017 |
candylips: let y = Ax^m y' = mAx^[m-1] y'' = m(m-1)Ax(m-2) substitute all and solve for the particular integral use Ax^3 + bx^2 + cx + d 1 Like |
Re: Do You Have Any Maths Question? Kindly Bring It On by mathefaro(m): 9:06am On Jan 09, 2017 |
thankyouJesus:Hmm! Boss! You dey scare me o |
Re: Do You Have Any Maths Question? Kindly Bring It On by logadims: 9:15am On Jan 09, 2017 |
thankyouJesus:how's school? |
Re: Do You Have Any Maths Question? Kindly Bring It On by thankyouJesus(m): 9:46am On Jan 10, 2017 |
logadims:Great, thank you. |
Re: Do You Have Any Maths Question? Kindly Bring It On by thankyouJesus(m): 9:47am On Jan 10, 2017 |
mathefaro:My boss 1 Like |
Re: Do You Have Any Maths Question? Kindly Bring It On by oxyoxyoxy: 7:15am On Apr 27, 2017 |
edusegzy: Nice to meet u here,i graduated from OAU too i am preparing for gre too bt i av issues with maths, can i av ur num so i can chat u up privately....my mail is wandeololade@ gmail .com...thanks |
Re: Do You Have Any Maths Question? Kindly Bring It On by Livebygrace: 6:50pm On Apr 27, 2017 |
U guys are doing great here. Keep it up. |
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