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Olabisi Onabanjo University(oou) 2018/2019 Admission / Federal University Oye-ekiti (FUOYE) 2018/2019 Admission Thread / 2018/2019 Admission Process Thread Guide (2) (3) (4)
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Re: UI 2018/2019 Admission Thread by Adelaide2001(m): 8:34am On Apr 12, 2018 |
DrBESTJC:Sorry this may be late but in my own opinion and according to Concord a singular subject must be followed by a singular verb.So the answer should be (B) |
Re: UI 2018/2019 Admission Thread by mrintellectual(m): 8:37am On Apr 12, 2018 |
IamGoke:You can change department in UI. It happens every year, especially if you have first class grade in 100 level 1 Like |
Re: UI 2018/2019 Admission Thread by Adelaide2001(m): 8:48am On Apr 12, 2018 |
afoobabs:Art Student dey here UI political science |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 9:27am On Apr 12, 2018 |
vicstiqs95:...yea..thank...but I think plant can synthesize oil while animal synthezie fat |
Re: UI 2018/2019 Admission Thread by Adelaide2001(m): 9:54am On Apr 12, 2018 |
Samsonyte: D B B C B |
Re: UI 2018/2019 Admission Thread by Adelaide2001(m): 9:55am On Apr 12, 2018 |
Samsonyte: D B B C B Please tell me if I am correct |
Re: UI 2018/2019 Admission Thread by IamGoke(m): 10:28am On Apr 12, 2018 |
mrintellectual: In the process of changing, is there a fee going to be paid?? thanks |
Re: UI 2018/2019 Admission Thread by hydee123(m): 11:19am On Apr 12, 2018 |
To get U.I PAST QUESTION CALL ME ON 08108775025 |
Re: UI 2018/2019 Admission Thread by afoobabs(m): 11:48am On Apr 12, 2018 |
Adelaide2001:at what time of the day well its better to be late than never |
Re: UI 2018/2019 Admission Thread by Adelaide2001(m): 12:16pm On Apr 12, 2018 |
afoobabs:My boss no vex I never knew there was a thread like this. |
Re: UI 2018/2019 Admission Thread by Aceed: 1:34pm On Apr 12, 2018 |
I know say e simple for una me still dey learn... A body of mass 25kg, moving at 3ms¹ on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. Calculate the coefficient of sliding friction [g=10ms²] The density of mercury is 1.36×10⁴kgm³ at 0°C. Calculate its value at 100°C and at 22°C. Take cubic expansivity of mercury as equal to 180×10^–6 K-¹. A brass measuring tape is correct at 20°C. The value obtained when the length of a field is measured with the rule at 50°C appears to be 70.5m. What is the true length of the field? Linear expansivity of brass = 1.8×10^-5 K-¹. PLEASE SHOW WORKINGS |
Re: UI 2018/2019 Admission Thread by Eben331: 5:28pm On Apr 12, 2018 |
Aceed:In question 2, what does the box represent? |
Re: UI 2018/2019 Admission Thread by Aceed: 5:38pm On Apr 12, 2018 |
Re: UI 2018/2019 Admission Thread by Eben331: 5:43pm On Apr 12, 2018 |
Aceed:Look at question 2, the density of mercury is what? |
Re: UI 2018/2019 Admission Thread by Eben331: 5:48pm On Apr 12, 2018 |
Aceed:(1) 0.18 (2) I dont know what you use the symbol 'box' to represent. Try to use dis formula: d1=d2(1+gamma*tita) use d1 to represent density of mercury at 0 degree celsius, d2 to rep density of mercury at 22 and 100 degrees celsius, where gamma=cubic expansivity (3) 70.46m |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 6:51pm On Apr 12, 2018 |
Eben331:....nice bro....pls show workings..ppl can learn from it...m busy now...wen m tru, I will solve it...if it tally wit urs, I won't post it... |
Re: UI 2018/2019 Admission Thread by Gracy3535(f): 7:35pm On Apr 12, 2018 |
Aceed:For no. 1 m=25kg, v=3m/s, s=2.5m, g=10m/s^2. Fm=1/2mv^2 F*2.5=1/2*25*(3)^2 F=25*9/5 where F=mg : 25*10=25*9/5 25*9/5 * 1/25*10 the 25 cancel out =9/50 =0.18 |
Re: UI 2018/2019 Admission Thread by Eben331: 8:43pm On Apr 12, 2018 |
Aceed:(1) m=25kg, u=3m/s, v=0m/s, s=2.5m, a=? using v^2=u^2+2as 0=3^2+2*a*2.5 0=9+5a 5a=-9 a=-9/5 a=-1.8m/s^2 Deceleration=1.8m/s^2sliding force=25*1.8=45N Recall:F=mu*R F=mu*m*g mu=F/mg mu=45/25*10 mu=45/250 mu=0.18 (no unit) |
Re: UI 2018/2019 Admission Thread by Eben331: 8:54pm On Apr 12, 2018 |
Aceed:(3) alpha=l2-l1/l1(t2-t1) where t=temperature 1.8*10^-5=70.5-l1/l1(50-20) 1.8*10^-5=70.5-l1/l1*30 1.8*30*10^-5*l1=70.5-l1 0.00054*l1=70.5-l1 0.00054l1+l1=70.5 1.00054l1=70.5 l1=70.5/1.00054 l1=70.46m True length=70.46m |
Re: UI 2018/2019 Admission Thread by Samsonyte(m): 8:55pm On Apr 12, 2018 |
afoobabs:correct boss |
Re: UI 2018/2019 Admission Thread by Eben331: 9:20pm On Apr 12, 2018 |
Pls help me out with this. What is the formula and dimension of Thrust, Energy density and Angular momentum? |
Re: UI 2018/2019 Admission Thread by Samsonyte(m): 9:36pm On Apr 12, 2018 |
Adelaide2001:no4 and 5 is correct, but no1, 2, 3 is wrong 1. C 2. A 3. C |
Re: UI 2018/2019 Admission Thread by Eben331: 10:07pm On Apr 12, 2018 |
Aceed:(3) density of mercury at 100 degrees celsius=1.33*10^2kgm^3 and density of mercury at 22 degrees celsius=1.35*10^2kgm^3 |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 10:20pm On Apr 12, 2018 |
Eben331:...Thrust is the same thing as force..dimension of force is MLT^-2....energy density= energy per unit volume....=ML^2T^-2/L^3...=ML^-1T^-2......angular momentum rep by L...L= Iw.. I= moment of inertia and w= angular frequency...I= mr^2 while w= 2πf...so L= mr^2(2πf)....2π is dimensionless...L= kgm^2/s unit...so dimension of L=ML^2T^-1....hope I try small... |
Re: UI 2018/2019 Admission Thread by afoobabs(m): 10:22pm On Apr 12, 2018 |
Adelaide2001: Samsonyte:look out for this guy samsonyte he is ur most vocal art/social science student here Samson the answer to question 1 is D oooo check this out
|
Re: UI 2018/2019 Admission Thread by Samsonyte(m): 10:27pm On Apr 12, 2018 |
afoobabs:u are right sir, it was a mistake boss. |
Re: UI 2018/2019 Admission Thread by Samsonyte(m): 11:03pm On Apr 12, 2018 |
1. What is the chance of choosing at random a three number which is divisible by 7? 2. A box contains 40 identical discs, some red and the rest white. if a disc is drawn at random, the probability that it is red is 1/4 . (a) How many white discs were in the box? (b) How many more red discs must be added to make P (red disc being picked) = 1/3? 3. Solve the equation a^2 - 8a + 12 = 0. Hence find the four values of x which satisfy the equation (x^2 - x)^2 - 8(x^2 - x) + 12 = 0. |
Re: UI 2018/2019 Admission Thread by Eben331: 11:29pm On Apr 12, 2018 |
Damayogenius18:You try pass small...Thanks bro...I knw dat thrust is the same as force bt pls show its formula. I think we can also say that angular momentum=mvr Am I wrong? P.S: You haven't pm me yet via my mail. |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 11:58pm On Apr 12, 2018 |
Eben331:..thrust is reaction force...formula is...rate of mass flow * velocity.... m/t * v.....angular momentum can be "mvr".. Remember L= Iw...=mr^2 * w.....but w= v/r...so L=mr^2 * v/r....=mr^2v/ r....= mrv.... PS...sori bro...I will l8ta |
Re: UI 2018/2019 Admission Thread by Adelaide2001(m): 12:37am On Apr 13, 2018 |
Samsonyte:Sir No(1) isn't C it is D also No(2) is not A.In a parliamentary system of government there are always two house for example in Britain we have the house of Lords & house of Commons or do you know any country practing Parliamentary system of Government that does not operate a bicameral legislature I think no (2) is B |
Re: UI 2018/2019 Admission Thread by hadebayor2606(m): 12:45am On Apr 13, 2018 |
08086095388 pls add me to whatsapp group |
Re: UI 2018/2019 Admission Thread by Damayogenius18: 1:13am On Apr 13, 2018 |
Guys...this issue abt O' level result upload... Av not uploaded my O level result which I did in 2015..when I filled the form I used awaiting result cos DAT day,I was not with my o level result..after jamb,I went for the upload and was told that there wasn't network...since then,I did not go...now, I heared that if u don't upload ur result and you used awaiting,even if one pass post utme,jamb won't give one admission at all...that the Caps system will sieve one...a guy said her sister experience that last yr...am really confuse...don't know wat to do...jamb said 20% that wrote jamb are SS2 student... I think that jamb has consider me as SS2 student....pls i need anybody to comment...don't wan2 waste my scores o... |
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