vaxx:
What will you pick?

C

dejt4u:
C

pretty, pls show your working steps

vaxx:
What will you pick?

C

kkins25:

C

please can you kindly demonstrate it?

-21m/11 * - 11/21 = 153/22 * - 11/21
M= - 51/2

please someone should help me out on good materials for NIGERIAN MATHEMATICS OLYMPIAD (JUNIOR) COMPETITION. THANKS

vaxx:
What will you pick?

C

tech18:

C

Everybody is picking c . Yes c is correct.

But the answer actually is -153/42. How do you put it in a mixed fraction?

vaxx:
Everybody is picking c . Yes c is correct.

But the answer actually is -153/42. How do you put it in a mixed fraction?

-153/42= - 51/14 (Dividing both d numerator and denominator by 3)

= - 3 9/14 ans

In a certain coordinate system {O, e₁, e₂, e₃}, where eᵢ, i ∈ {1, 2,3,4} denotes unit vectors and O the origin.
Three vertices of a parallelogram ABCD are given as A(0, 1, -1) B(1, 0, 2) and C(2, 3, 0).

Find the coordinates of the point D.

someone should help me with dis ss1 mathematics
1) four angles of a Pentagon are equal and the fifth is 60degree. find the equal angles and show that two sides of the Pentagon are parallel
2) A regular polygon has an angle of size 160degree each.How many sides does the polygon have?
3) A regular polygon of n sides has each exterior angle to be 45degree.find the value of n

Hi, great minds. Please I need help with this assignment.

find the positive value of C if the expression (2C+3)y² -6y+4-c is perfect square

DBright123:
Hi, great minds. Please I need help with this assignment.

find the positive value of C if the expression (2C+3)y² -6y+4-c is perfect square

(2C+3)y² - 6y + (4-C),
for a perfect square, b² = 4ac ........*
a = 2C+3, b = -6, and c = 4-C,

sub. these in eqn *;
b² = 4ac
(-6)² = 4 × (2C+3) × (4-C),
36 = 4(2C+3)(4-C),
36 = 4(8C -2C² +12 - 3C),
36 = 4(12 + 5C - 2C²),
36 = 48 + 20C - 8C²,
8C² - 20C - 48 + 36 = 0,
8C² - 20C - 12 = 0,
divide through by 4;
2C² - 5C - 3 = 0 .........**

solving eqn ** quadratically;
C = 3 or -½

dejt4u:
(2C+3)y² - 6y + (4-C), for a perfect square, b² = 4ac ........* a = 2C+3, b = -6, and c = 4-C,
sub. these in eqn *; b² = 4ac (-6)² = 4 × (2C+3) × (4-C), 36 = 4(2C+3)(4-C), 36 = 4(8C -2C² +12 - 3C), 36 = 4(12 + 5C - 2C²), 36 = 48 + 20C - 8C², 8C² - 20C - 48 + 36 = 0, 8C² - 20C - 12 = 0, divide through by 4; 2C² - 5C - 3 = 0 .........**
solving eqn ** quadratically; C = 3 or -½

Thank you so much, I really appreciate.

OK

Please can someone help me with this in the picture. Solve using logarithm table. My problem is the subtraction and addition signs in the questions.

paulmarkino:
Please teachers, who can share me soft copy of first term question papers for senior secondary 1, 2 and 3. Email address is paulmarkino@gmail.com or WhatsApp me on 08032334579

dont be a lazy teacher. type the questions yourself

Tpappie:



dont be a lazy teacher. type the questions yourself

Boss am not a teacher. I just want to be able to solve such questions. I don't want to make it like I set up the question.

paulmarkino:

Boss am not a teacher. I just want to be able to solve such questions. I don't want to make it like I set up the question.

Ok bro. Nice one then . I teach A level and Junior school 3, would have sent seniors for you if I had it .

paulmarkino:
Please can someone help me with this in the picture. Solve using logarithm table. My problem is the subtraction and addition signs in the questions.

Here:

Here

Check

Maths gurus plz help x+y= 5 y^2+x^y=17 Find x and y x=2,y=3 x=3,y=2
Plz help me out. thanks in advance.

Mechanics96:

Here:

My brother God bless you. It is so right and perfect. �

Wow! Sounds like fun!

Mathematicians please help out.. Its quite urgent

p^2 + q^2 = 11pq, where P and Q are constants show that 1/2(LogP + log Q) equals
a) Log(p - q)/3
b) Log (p - q)/√13

P.S: If possible solutions should be hand written snapped and uploaded for better comprehension
Thanks.

Aguemma:
Maths gurus plz help x+y= 5 y^2+x^y=17 Find x and y x=2,y=3 x=3,y=2
Plz help me out. thanks in advance.

can you write it on a sheet of paper and snap?

ugo4u:
Mathematicians please help out.. Its quite urgent

p^2 + q^2 = 11pq, where P and Q are constants show that 1/2(LogP + log Q) equals
a) Log(p - q)/3
b) Log (p - q)/√13

P.S: If possible solutions should be hand written snapped and uploaded for better comprehension
Thanks.

Easy

Aguemma:
Maths gurus plz help
x+y= 5
y^2+x^y=17
Find x and y
x=2,y=3
x=3,y=2

Plz help me out.
thanks in advance.

The pairs (x, y) = (2, 3), (3, 2) are indeed solutions to the system. It remains to show that they're the only solutions to the system.
To do this, it is enough to prove that if a solution to the above system exists, then they must be positive integers. Indeed, from x + y = 5. We deduce that the pair (x, y) must be rational numbers. On the other hand, from x² + x^y = 17, we get x^y = 17 -x² from this we deduce that x and y must be positive integers for it that were not the case, the number x^y is irrational while 17 - x² would be rational and equality cannot hold. And this completes the proof.

For everyone.

Please who can teach me mathematical induction....My whatsapp number is 08143814054
Thanks

LogRhythm:

I got the same too...i mailed leadway but I haven't gotten any response from them...have u been able to solve urs?
My WhatsApp line is 08066563331