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Nairaland Forum / Nairaland / General / Education / Mathematicians In The House,solve This Permutation Problem (662 Views)
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Mathematicians In The House,solve This Permutation Problem by sunnychibs(m): 11:30am On Jul 22, 2019 |
in how many ways can 6 colored chalks be arranged if 2 are of the same color? Show working |
Re: Mathematicians In The House,solve This Permutation Problem by Inspectorsuga22(m): 11:37am On Jul 22, 2019 |
Uncle I'm not seeing well n my biro is not writing well too... When I come tomorrow I will copy the correction... 1 Like |
Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 12:33pm On Jul 22, 2019 |
AABCDE 6!/(2!)=sum of angles at a point. Explanation 6 chalks can be arranged in 6! Ways So we will divide by the how many way each of the identical item can be arranged Identical here is AA it can be arranged in 2! ways Thus =6!/2!=6×5x4x3=360ways @sunnychibs 2 Likes |
Re: Mathematicians In The House,solve This Permutation Problem by Martinez39(m): 9:13pm On Jul 22, 2019 |
sunnychibs:6! ÷ 2! = 360 ways |
Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 12:40am On Jul 23, 2019 |
This question is quite vague. It is not even clear whether the two monochromatic chalks are to be always placed together or not. The possible answers are 5!/2 and 6!/2 according as whether the monochromatic chalks are to be or not to be placed together. |
Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 6:13am On Jul 23, 2019 |
MathsEconomics:Yes broda its not complete |
Re: Mathematicians In The House,solve This Permutation Problem by Olorunnim: 10:13am On Jul 23, 2019 |
Uncle my biro haf finish |
Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 11:28am On Jul 23, 2019 |
MathsEconomics:It is clear, when no condition is attached You do it for they can be placed or they can't be placed together. The question is very correct. |
Re: Mathematicians In The House,solve This Permutation Problem by Gorioye: 3:58pm On Jul 23, 2019 |
6!/2!2! 6x5x4x3x2x1/2x1x2x1 6x5x4x3/2x1 360/2 = 180 Q.E.D. |
Re: Mathematicians In The House,solve This Permutation Problem by CodeTemplar: 5:46pm On Jul 23, 2019 |
360 |
Re: Mathematicians In The House,solve This Permutation Problem by Nobody: 6:42pm On Jul 23, 2019 |
Gorioye:Note correct |
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