Hi everyone.. Good morning. I need a screen replacement for my Realme GT Neo 2 5G (Model RMX 3370). Please reach out to me if you have one available or if you can direct me to the right persons I'll very much appreciate that. Many thanks.

Meister:


Yeah but I'm about to get it from another source shaa

Alright boss.. Cheers ��

Meister:


So na you buy that Realme that I've been eyeing

Haa, no vex o boss.. Were you going to buy from the same seller?

Lilsameey:
Oh, that's great.

Many thanks once again chief. He was out of stock again the week after so I settled for Realme GT Neo 2 12/256GB thanks to the seller recommendation.

womenareapez:
don't go fall scam to all those scammer and come here next thing to say this contact scammed you

Follow through recommended smaller on this platform and don't make your greediness scamm you.


Wisdom is profitable

Yeah, thanks for the heads-up.

Lilsameey:
No worries man, You reached out to him?

Yeah I did. He's out of stock for now. Said he'll restock next week.

Lilsameey:
Here's his whatapp

Many thanks Chief.

Lilsameey:
Yes,...A seller here on Nairaland. If you want make I connect you, Let me know.

Please do, I'll appreciate that.

Lilsameey:
N195k

Is it the 8/256GB variant? And where did you get it at this price?

frankyvalll:
Poco F3

8/256 = ₦200k (Ocean blue & Night Black)

Poco X3 pro

8/256 = ₦140k

Redmi Note 11

6/128 = ₦ 110k

Redmi Note 10 pro

6/128 = ₦ 140k

contact 08038784508

Is the Poco X3 pro you've got a brand new one?

Nu3L:


Is it the 12.0.3 with the security patch or the one of android 11?

The one with the security patch.

amnwa:
Abeg who on note 9s has done the 12.0.3 update. How's it like ? Is it stable?

Battery lasts much longer now.

Any seller with Redmi 5A battery for sale please quote me..

Great question OP.. This is going to be a really long read, but it's worth it.

This question is more of mathematics and thus requires sound understanding of the axioms of mathematics to make sense of what's going on. I don't want you to appeal to a physical interpretation by trying to relate this with something real, something you can touch or something you can relate with. Mathematics is beyond all of this.

Alright, lemme introduce you to Abstract Algebra, or just Algebra. This is a field of study in mathematics that deals with algebraic structures (will explain what this means shortly) and the various operations that can be done in these algebraic structures. Basically, these structures are just abstract entities with well-defined axioms that describes them.

Now for starters, you may be wondering what an axiom is.

An axiom is a statement or proposition that is well accepted based on logical inference and is self-evidently true, but can not be proved.

Now, something about axiom is that, it is the foundation of all of mathematics, infact all of mathematics is built on well-defined axioms, from these axioms, theorems and conjectures are built to produce everything we've ever known in mathematics. So without axioms, there is no mathematics. Second is, axioms can't be proved, so these axioms must be well thought out by mathematicians before they are established. So as a mathematician, you don't worry about whether or not an axiom is true cause all of that has been handled by mathematicians. You just agree that these axioms exists and are self-evidently true. So if you take this statement as an axiom "X is even" you don't worry yourself over whether X can be odd at times, you just go ahead and work with the assumption that "X is even" must be true.

So with that out of the way, I think it's time to introduce some of the algebraic structures we have in abstract algebra. These are just 3 of them: Groups, Rings, Fields. I don't know if there are others cause I'm not a mathematics student. But the algebraic structure of concern for today is Groups.

Now, what is a Group? A group, just like every other algebraic structure, is an algebraic structures with some well-defined axioms. Aha, now what makes a Group different from a Ring and a Field, it's the axioms that define these groups. These axioms are somewhat different for the different algebraic structures. That's exactly what makes them different. So a Group is essentially an algebraic structure that contains a set (just the usual notion of set you've learnt), say G, and an operation, let's call this operation *, with some specific axioms. Now what are those axioms.

1.) Closure
2.) Associativity
3.) Existence of identity element that's always unique.
4.) Existence of an inverse, that's also unique for each element in G.

So a Group contains: a defined Set, say G, a single operation, say *, and some axioms that shows how these operations are carried out. Everything outside of these is meaningless to a group. It's from these concept that we'll build everything we know about a Group.

First, what does a set have to do with this? and what is even an operation to begin with? A set is just a fancy name for a collection of stuffs, I'm sure you have an idea of what set is and have probably carried out some "operations on set". So we introduced a set to contain some stuffs, these are called elements of the set, and it's these elements that'll carry out these operations self, so it's really important. Now, what's an operation, an operation can be something like "addition", where you just add up two things together, "multiplication" where you're required to just multiply things, and so on. Now, the question is, what's the definition of addition and/or multiplication in the first place. Are there axioms for these two things, now that's exactly what this axioms will describe completely. So you see why it's important we do all these?

Let's say our set G contains three elements, "a" and "b" and "c". To write this mathematically, we say:

G = {a, b, c} and the operation on this group is called , *. Don't be bothered about what this operation is at all.

Ohh, and mathematically, to write that a, b belongs in G, we say: a ∈ G and b ∈ G. Simple right? Now let's continue and explain what this axioms mean.

The first Axiom is closure:

Closure means that, when you take any two elements in the set G, an operation under those two elements will produce another element, and this new element belongs in this same group. Mathematically you write it this way:

if a ∈ G and b ∈ G, then a * b is another element, that belongs in G, simple right? So that basically means "a" and "b" can't just be the only members in G, it keeps expanding as we take up more axioms. But this is basically what the axiom of closure is all about.

Now moving to the second axiom, associativity. This particularly axiom involves three elements. Hence why I started out with three elements in G. So let's see what this axiom states. It goes like this.

if a, b and c belongs in G, then: a * (b * c) = (a * b) * c.

So what does this statement literary mean? It means that if I take two elements in a group for example, b and c, and I do an operation, *, under them, the closure axiom guarantees us that b * c, belongs in the group. Now, don't forget that b * c is just one single element in G, so if I do another operation with "a" under *, it'll give me another element in the group called a * (b * c) since we assumed that closure is true. Now, consider the other way, if I operate "a" and "b" first, then I combine this result with "c" it'll give me (a * b) * c, so the axiom is telling us that both these results are equal and the same. It's as simple as that, no more no less, trying to relate this with our five senses and physical reality just doesn't work. That's what the axiom says and that's what we must work with.

Now for the third axiom, first in mathematics, when they say something is unique, it means there's one and only one of that thing. So identity element being unique means there can only be a single identity element in a group. Usually the identity element is symbolically written as "e". So we just agree with this convention and move on. Now what does being an "identity element" even mean. That's what the statement of this axiom is. We know that "a" belongs in G, also our new element, e, belongs in G, an identity element is something that goes this like this:

a * e = e * a = a For all "a" that belongs in G

What does this even mean, it simply states that when you operate any element in G, let's say element "a" for example, with the identity element "e" in whatever way, whether a * e or e * a, at the end of the day, it preserves "a", that is, "a" doesn't change at all. So if I operate element "b" with the identity element, the output is "b" if I operate "c" with the identity element, the output is still "c".

You'll like to ask, have I seen something similar to this before, yes you have. Think of it, if the operation, *, is "addition", what's the identity element? It's 0 of course.. because when you add 0 to any number, it doesn't change that number. Lol, now the thing is, 0 was chosen to play this role in mathematics. It could've been given any other symbol but that symbol and name was just chosen.

How about if that operation, *, is multiplication, what's the inverse of multiplication, it's 1 of course. Because when you multiply 1 by any number, the output is still that number. Aha, now let's not just stop here, there is one more axiom remaining.

Now for the 4th axiom. This one is about another element again that's in G. Lets symbolise that inverse element with M. Now, here's what it means to be an inverse element under operation, *.

a * M = M * a = e.

Aha, what this means is that our set G contains an inverse element, M, which when operated with "a" gives the identity element. Now each element in its own inverse ohh, it's different from identity element where the whole set G share the same identity element. So "a" has its own inverse and is unique (which means "a" has a single inverse), "b" has its own unique inverse, "c" has its own too and so on.

Now this may already look too abstract to you, is there something I can relate this with? Of course this is, now let's say the operation, *, we're talking about is addition operation. What's the inverse? That is? What's that element which when added to "a" will give the identity element for addition (which is zero) that element is simply (–a). And that's because we know that: a + (–a) = 0. So the inverse of 5 is –5, the inverse of 2 is –2. And so on.

How about multiplication, does it have an inverse too? Yes it does, the inverse under the operation of multiplication is "1/a" for "a" and that's because when you multiply "a" and "1/a" it'll give you 1, which is the identity element under multiplication. Although if you assume that 0 belongs in this group G, under the operation of multiplication, it has no inverse. The reason is not farfetched. 1/0 is meaningless in mathematics and that's because division of any number by 0 is not allowed in mathematics.

Now we are armed to the teeth and we can tackle your question more properly. Now that we know what a group is all about, to restate it so as to be sure, a group is a structure with a set G and a single operation, say *, that obeys all those axioms we stated.

We can now ignore those flimsy pictures we were trying to paint with the "2 things in zero place OR zero in three places". Let's work with this algebraic structure at out disposal and figure it out once and for all.

Let's say we have a group called (G, *), actually this is how groups are represented in mathematics. G is the set, and * is the operation under G. Now let's start with operation of addition, which is represented by +.

So what is 1 + 0? Remember we said 0 is the identity element under +, and we said (identity element axiom) that:

a * e = a,

so 1 + 0 = 1.

It's easy now to see that: 0 + 0 = 0.

..

Gemineye:
I'm unable to uninstall chrome self...i just disabled dual apps and was good to go

Nice.. Good to know you've fixed it.

Gemineye:
Google chrome is multiplying in my phone oo how do i uninstall all these

The option for uninstall is not showing

I even checked dual apps, it's still not showing there. The only dual app i created was Whatsapp

The apps on the first two rows are your recent apps. So they shouldn't count in the total number of chrome apps currently installed. Uninstall the chrome app with the dual-app logo and you're good to go.

Very educative.. Thanks Op.

frankyvalll:
will be available from weekend

Alright, will look forward to it.

frankyvalll:
none available for now

How about Redmi 8A?

Used Redmi 8A needed urgently. Quote me with the price if you have one ready.

Is Redmi 8 still available? If yes, how much does a unit cost? I mean just the phone as you mentioned.

GrandMufti:

Your number ends with 203? What network?

I can't contain my joy sir, I'm saying thank you with all of my heart, I will never forget this. May God bless you beyond your expectations, even when you least expect it. Thank you once again sir ���

GrandMufti:

Your number ends with 203? What network?

Please don't send airtime to that line sir, I'm yet to pay my debt. I really appreciate your kind gesture sir.. God bless you richly.

GrandMufti:


Ok... Press and hold the power button till phone vibrates

I've rebooted the phone. All that is left is to confirm if the issue has been fixed, I'd have placed a call through to ascertain if the issue has been fixed but I don't have airtime. But I'll reach out to you when the next call comes through, Many thanks once again sir.

GrandMufti:


Have you tried rebooting?

Come to think of it, I haven't done that.. I'll do that and get back to you after the next call comes through. Many thanks sir.

Good day everyone.. I need your help on this issue. I recently noticed that whenever I'm in a call, I have to make sure my phone is on loudspeaker before the other party can hear me. It's a Redmi 5A device by the way, and the last time I updated the software was a longtime ago, probably 1 year already, but the issue is just of recent. Software is currently running MIUI 11. Any help will be appreciated.

Happy New year everyone.. Greater heights for us all this year. Cheers.

jboixxx:
Correct feedback that encourages more support.
Enjoy that device boss

I will my boss, thank you very much.. Those guys were very helpful and patient with me when I had that issue. That's why I had to come back to say thank you even if that's the least I could do.

genius43:


Remove mobile data restrictions from all of them. You did it with your own hands.

Many thanks my boss, I eventually had to reboot the phone to factory mode, flashed the whole content and everything went back to normal. Thanks for your suggestions sir, I'm really grateful.