Just a little for the weekend,the first person to provide correct solution will be awarded......NOTE;show ur workings clearly with phone number (Mtn)

.

Mosetgg:
Just like asking Buhari to reverse the oil price to 40 naira pay liter and to explain clearly how he would do it.

honestly Buahri is capable to do it if He want to.

attempted: phone number: 080--69--00--28--32

I = V/R= 12/(5+20) = 0.48A

V=IR = 5 * 0.48 = 2.4v

Voltmeter reading = (12 - 2.4)v = 9.6v

Backcheck:
I = V/R= 12/(5+20) = 0.48A

V=IR = 5 * 0.48 = 2.4v

Voltmeter reading = (12 - 2.4)v = 9.6v

wrong

brisstone:
attempted:
phone number: 080--69--00--28--32

i am not after final ans but workings,u got the final ans right but your workings is faulty

I have the solution with me

#

brisstone:
#

ur workings is faulty,this is a voltmeter circuit not electric cell

Ah no well but you still fit send me the recharge card.

NDSMELODY:
Just a little for the weekend,the first person to provide correct solution will be awarded......NOTE;show ur workings clearly with phone number (Mtn)

V_m = V₁ × { R₂R_m/(R₂R_m + R₁(R₂ + R_m)) }
R_m is the resistance of the meter

V₁ = 12 V
R₂ = 20 mΩ = 0.02 Ω
R₁ = 5 mΩ = 0.005 Ω
R_m = 5 mΩ = 0.005 Ω

V_m= 12 V × {(0.02 Ω × 0.005 Ω)/(0.02 Ω × 0.005 Ω) + 0.005 Ω (0.02 Ω + 0.005 Ω)

V_m = 12 V × {0.0001/0.0001 + 0.000125)
V_m = 12 V × {0.0001/0.000225}
V_m = 12V × 0.444
V_m = 5.33 V


Phone no: 09062114822 - MTN

Kareayo:

V_m = V₁ × { R₂R_m/(R₂R_m + R₁(R₂ + R_m)) }
R_m is the resistance of the meter

V₁ = 12 V
R₂ = 20 mΩ = 0.02 Ω
R₁ = 5 mΩ = 0.005 Ω
R_m = 5 mΩ = 0.005 Ω

V_m= 12 V × {(0.02 Ω × 0.005 Ω)/(0.02 Ω × 0.005 Ω) + 0.005 Ω (0.02 Ω + 0.005 Ω)

V_m = 12 V × {0.0001/0.0001 + 0.000125)
V_m = 12 V × {0.0001/0.000225}
V_m = 12V × 0.444
V_m = 5.33 V


Phone no: 09062114822 - MTN

wrong

I will not receive any solution after i posted mine

here
@ndsmelody
I no get mtn sim

NDSMELODY:
Just a little for the weekend,the first person to provide correct solution will be awarded......NOTE;show ur workings clearly with phone number (Mtn)

How much card?

NairalandSARS:

How much card?

solve first

Is this correct?

This should be correct.

Apreecauts:
Is this correct?

wrong

fmcjunior:
This should be correct.

wrong

Should i post solution?

NDSMELODY:
Should i post solution?

my solution is correct sir!

SPLENDID25:
my solution is correct sir!

no it is not sir

Should i post solution?

NDSMELODY:
Should i post solution?

Yes

NDSMELODY:
no it is not sir

like seriously?but a check said otherwise..... post your answer then!

Here is my solution

NDSMELODY:
Here is my solution

mr! those resistors are in series, aren't they? i can be schooled tho.

SPLENDID25:
mr! those resistors are in series, aren't they? i can be schooled tho.

bro! The internal resistor of the meter is in parallel with the 5ohm resistor,so u calculate the total resistor first and then use voltage divider rule to measure output voltage across 5ohm resistor since the meter was placed across it.....note you can labell 20ohm resistor as R1 and R total as R2....i stop here!

NDSMELODY:
bro! The internal resistor of the meter is in parallel with the 5ohm resistor,so u calculate the total resistor first and then use voltage divider rule to measure output voltage across 5ohm resistor since the meter was placed across it.....note you can labell 20ohm resistor as R1 and R total as R2....i stop here!

I am late sha, any other cct question...you can tag me