First person to provide solution will be awarded.....Note; show your workings clearly with phone number (MTN)

NDSMELODY:
First person to provide solution will be awarded.....Note; show your workings clearly with phone number (MTN)

1/R = 1/R_b + 1/R_m
1/R = 1/5 + 1/2
1/R = (2+5)/10
R = 10/7 = 1.43 kΩ


V_o = {5/(25+1.43)} × 30
V_o = 5.68 V

Phone no: 09062114822 - MTN

Kareayo:
1/R = 1/R_b + 1/R_m 1/R = 1/5 + 1/2 1/R = (2+5)/10 R = 10/7 = 1.43 kΩ

V_o = {5/(25+1.43)} × 30 V_o = 5.68 V
Phone no: 09062114822 - MTN

wrong

QueenXtar:
check

wrong

NDSMELODY:
First person to provide solution will be awarded.....Note; show your workings clearly with phone number (MTN)

Sensitivity, S = 0.1 kΩ/V
V_s = {5/(25+5)} × 30 V = 5V
R_s = 0.1 kΩ/V × 5V = 0.5 kΩ


1/R = 1/R_b + 1/R_m + 1/R_s
1/R = 1/5 + 1/2 + 1/0.5
1/R = 2.7
R = 1/2.7 = 0.37 kΩ


V_o = {5/(25+0.37)} × 30
V_o = 5.912 V



Phone no: 09062114822 - MTN

Kareayo:
Sensitivity, S = 0.1 kΩ/V V_s = {5/(25+5)} × 30 V = 5V R_s = 0.1 kΩ/V × 5V = 0.5 kΩ

1/R = 1/R_b + 1/R_m + 1/R_s 1/R = 1/5 + 1/2 + 1/0.5 1/R = 2.7 R = 1/2.7 = 0.37 kΩ

V_o = {5/(25+0.37)} × 30 V_o = 5.912 V


Phone no: 09062114822 - MTN

wrong

How can I be solving someone's assignment just because of 200 naira recharge card?

Tufiakwa.

bluefilm:
How can I be solving someone's assignment just because of 200 naira recharge card?

Tufiakwa.

i do not know how this negative thought came out from ur mind,what u dnt know is that i have the solution with me already i am only doing this from passion.do you remember that no tertiary institution is session talkless of giving out assignment to their student because the question above is not from secondary school as you think.......if u cannt solve it just view and leave, you do not need to distrupt the open minded people that will try their luck...have a good day.

NDSMELODY:
i do not know how this negative thought came out from ur mind,what u dnt know is that i have the solution with me already i am only doing this from passion.do you remember that no tertiary institution is session talkless of giving out assignment to their student because the question above is not from secondary school as you think.......if u cannt solve it just view and leave, you do not need to distrupt the open minded people that will try their luck...have a good day.

Nwoke m go and do your assignment and leave me alone.

You want me to come here and be solving your EE251 assignment for you just for 200 naira airtime abi?

School wan resume now naim you come remember say dem give una assignment wey you never do, so you come carry am come nairaland make boys help you solve am on the promise of 200 naira recharge card.

Guy abeg no make me vex for you o.

bluefilm:


Nwoke m go and do your assignment and leave me alone.

You want me to come here and be solving your EE251 assignment for you just for 200 naira airtime abi?

School wan resume now naim you come remember say dem give una assignment wey you never do, so you come carry am come nairaland make boys help you solve am on the promise of 200 naira recharge card.

Guy abeg no make me vex for you o.

would you like me to provide solution right now?..........

NDSMELODY:
First person to provide solution will be awarded.....Note; show your workings clearly with phone number (MTN)

Sensitivity=0.1kπ/V

Internal resistance of the meter=maximum voltage range *sensitivity
rm= 10*0.1=1kπ

Rt= (Ra *rm)/(Ra+rm)
Rt=(1*5)/(1+5)=0.83kπ

USING POTENTIAL DIViDER RULE,

Vm= (30 * 0.83)/(0.83+2)
Vm=8.799V.

Hence, the reading of the meter Is 8.799v

Airtel===08122980420

kolad59:

Sensitivity=0.1kπ/V
Internal resistance of the meter=maximum voltage range *sensitivity rm= 10*0.1=1kπ
Rt= (Ra *rm)/(Ra+rm) Rt=(1*5)/(1+5)=0.83kπ
USING POTENTIAL DIViDER RULE,
Vm= (30 * 0.83)/(0.83+2) Vm=8.799V.
Hence, the reading of the meter Is 8.799v
Airtel===08122980420

wrong

Any other solution after i have posted mine wnt be awarded.

NDSMELODY:
would you like me to provide solution right now?..........

No.

Wait lemme solve it for you first

bluefilm:


No.

Wait lemme solve it for you first

if you get it right i will double the amount

NDSMELODY:
if you get it right i will double the amount

Sure

bluefilm:

Sure

sure

Resistance in parallel sec= ((5*10^3)*(2*10^3))/(5*10^3)+(2*10^3)

=1.429kohms

the voltage on the meter now is
=(1.429*10^3)*30V/(25*10^3)+(1.429*10^3)
= 1.62V

08132209303 MTN

Ugobest101:
08132209303 -MTN

where is your solution

Solving for Resistance in Parallel first gives:

1/5 + 1/2 = 7/10

Therefore, inverting the result gives Resistance in Parallel = 10/7 Kohms

Total Resistance in the circuit = 25 Kohms + 10/7 Kohms = 185/7Kohms

Applying ratios...

Voltage across multimeter = (Resistance across multimeter/Total Resistance in the circuit) * 30V

= [ (10/7) / (185/7) ] * 30
~ 1.6216 V

Ugobest101:
Resistance in parallel sec= ((5*10^3)*(2*10^3))/(5*10^3)+(2*10^3)

=1.429kohms

the voltage on the meter now is
=(1.429*10^3)*30V/(25*10^3)+(1.429*10^3)
= 1.62V

08132209303 MTN

wrong

bluefilm:
Solving for Resistance in Parallel first gives:

1/5 + 1/2 = 7/10

Therefore, inverting the result gives Resistance in Parallel = 10/7 Kohms

Total Resistance in the circuit = 25 Kohms + 10/7 Kohms = 185/7Kohms

Applying ratios...

Voltage across multimeter = (Resistance across multimeter/Total Resistance in the circuit) * 30V

= [ (10/7) / (185/7) ] * 30
~ 1.6216 V

wrong,is this how i will score zero if it is an assignment?

Should i post my own solution?

NDSMELODY:
wrong,is this how i will score zero if it is an assignment?

kolad59:
this should be write, I didn't add the Rm=2kπ in my workings

Sorry, I missed the sensitivity factor

So, here's it again

Solving for the sensitivity factor, the resistance of the voltmeter = 0.1 * 10 = 1Kohm

Therefore total resistance of the Voltmeter = 2 + 1 = 3Kohms

Now solving Resistance in Parallel first gives:

1/5 + 1/3 = 8/15

Therefore, inverting the result gives Resistance in Parallel = 15/8 Kohms

Total Resistance in the circuit = 25 Kohms + 15/8 Kohms = 215/8Kohms

Applying ratios...

Voltage across multimeter = (Resistance across multimeter/Total Resistance in the circuit) * 30V

= [ (15/8 ) / (215/8 ) ] * 30
~ 2.093 V

bluefilm:


Sorry, I missed the sensitivity factor

So, here's it again

Solving for the sensitivity factor, the resistance of the voltmeter = 0.1 * 10 = 1Kohm

Therefore total resistance of the Voltmeter = 2 + 1 = 3Kohms

Now solving Resistance in Parallel first gives:

1/5 + 1/3 = 11/15

Therefore, inverting the result gives Resistance in Parallel = 15/11 Kohms

Total Resistance in the circuit = 25 Kohms + 15/11 Kohms = 290/11Kohms

Applying ratios...

Voltage across multimeter = (Resistance across multimeter/Total Resistance in the circuit) * 30V

= [ (15/11) / (290/11) ] * 30
~ 1.5517 V

this should be write, I didn't add the Rm=2kπ in my workings

bluefilm:




Sorry, I missed the sensitivity factor

So, here's it again

Solving for the sensitivity factor, the resistance of the voltmeter = 0.1 * 10 = 1Kohm

Therefore total resistance of the Voltmeter = 2 + 1 = 3Kohms

Now solving Resistance in Parallel first gives:

1/5 + 1/3 = 8/15

Therefore, inverting the result gives Resistance in Parallel = 15/8 Kohms

Total Resistance in the circuit = 25 Kohms + 15/8 Kohms = 215/8Kohms

Applying ratios...

Voltage across multimeter = (Resistance across multimeter/Total Resistance in the circuit) * 30V

= [ (15/8 ) / (215/8 ) ] * 30
~ 2.093 V

wrong

kolad59:
this should be write, I didn't add the Rm=2kπ in my workings

wrong

Should i provide my solution?

NDSMELODY:
wrong

Bye bye

I no do again

bluefilm:

Bye bye
I no do again

eyah,can i provide my solution now?

NDSMELODY:
eyah,can i provide my solution now?

Yes, please.