Richiez: @everyone, sorry for my disappearing act, i was fixing my modem. i'm back so let's roll

abeg o. Help me fix my problems. E still plenty wey i need post

Richiez: @Ghetoguru, see how u destroyed that math question. i salute you sir

Just doing what I learnt from you guys I greet you!

yungryce: abeg o. Help me fix my problems. E still plenty wey i need post

okay bro, just post them neatly here in a way that i can interprete them.

A mathematician organizes a lottery in which the prize is an infinite amount of money. When the winning ticket is drawn, and the jubilant winner comes to claim his prize, the mathematician explains the mode of payment: "1 dollar now, 1/2 dollar next week, 1/3 dollar the week after that..."

Mathematicians and assumption sef, chai!

A mathematician, an engineer, and a chemist were walking down the road when they saw a pile of cans of beer. Unfortunately, they were the old-fashioned cans that do not have the tab at the top. One of them proposed that they split up and find can openers. The chemist went to his lab and concocted a magical chemical that dissolves the can top in an instant and evaporates the next instant so that the beer inside is not affected. The engineer went to his workshop and created a new HyperOpener that can open 25 cans per second.
They went back to the pile with their inventions and found the mathematician finishing the last can of beer. "How did you manage that?" they asked in astonishment. The mathematician answered, "Oh, well, I assumed they were open and went from there."

A mathematician and a physicist agree to a psychological experiment. The (hungry) mathematician is put in a chair in a large empty room and his favorite meal, perfectly prepared, is placed at the other end of the room. The psychologist explains, "You are to remain in your chair. Every minute, I will move your chair to a position halfway between its current location and the meal." The mathematician looks at the psychologist in disgust. "What? I'm not going to go through this. You know I'll never reach the food!" And he gets up and storms out.
The psychologist ushers the physicist in. He explains the situation, and the physicist's eyes light up and he starts drooling in excitement. The psychologist is a bit confused. "Don't you realize that you'll never reach the food?" T he physicist smiles and replies: "Of course! But I'll get close enough for all practical purposes!"

Have fun!. all work without play makes jack a dullard

Richiez: A mathematician and a physicist agree to a psychological experiment. The (hungry) mathematician is put in a chair in a large empty room and his favorite meal, perfectly prepared, is placed at the other end of the room. The psychologist explains, "You are to remain in your chair. Every minute, I will move your chair to a position halfway between its current location and the meal." The mathematician looks at the psychologist in disgust. "What? I'm not going to go through this. You know I'll never reach the food!" And he gets up and storms out.
The psychologist ushers the physicist in. He explains the situation, and the physicist's eyes light up and he starts drooling in excitement. The psychologist is a bit confused. "Don't you realize that you'll never reach the food?" T he physicist smiles and replies: "Of course! But I'll get close enough for all practical purposes!"

This is funny... Made me think, there is actually an infinite array of numbers between 1 and 2. But we count 1, 2, 3, 4, .... like say he easy, lol

wow! i really missed out on this maths frenzy maths is so fun that it became a past time back then in school. right now am just wallowing in nostalgia of the abstract/complex maths i did during my MSc in control systems engineering.i would love to be part of this but right now am way 2busy. i hail all the guru that is making things happen. maybe i will be recommending you guys for the Melina maths prize .
just hv these few contribution to make
for;
i) X^2=2^X
apart from numerical solution (graphical, etc) it can also be solved by differentiating twice and solving for X

ii) 3^X +2^X=5^x this can also be solved by playing around diff.

^^^

doubleDx:

I used .gif.

3^x + 2^x = 5^x

To plot these graphs, you will need a table of values for 5^x and 3^x + 2^x

To create the table, you will give x a range of values, say from -2 to 2 and calculate the corresponding values of each of the equation by substituting each value of x in the equations.

For the graph 5^x,
Lets subtitute the value of x each from -2 to 2

When x = -2
5^x = 5^(-2) = 1/5^2 = 1/25
3^x + 2^x = 3^(-2) + 2^(-2) =1/9 +1/4 = 13/36

When x = -1
5^x = 5^(-1) = 1/5^1 = 1/5
3^x + 2^x = 3^(-1) + 2^(-1) =1/3 +1/2 = 5/6

When x = 0
5^x = 5^(0) = 1
3^x + 2^x = 3^0 +2^0 = 1+ 1 = 2

When x =1
5^x = 5^(1) = 5
3^x + 2^x = 3^1 + 2^1 = 5

When x = 2
5^x = 5^2 = 25
3^x + 2^x = 3^2 + 2^2 = 13

And so on.....

x = -2 , -1, 0, 1, 2
5^x = 1/25, 1/5, 1, 5, 25
3^x + 2^x = 13/36, 5/6, 2, 5, 13

If you plot these two graphs with the above table, they will intersect at x = 1, i.e when their values at x = 1 are the same. So the value of x at their point of intersection is your answer, which is 1. If you notice at x = 1, 3^x + 2^x = 5 and 5^x = 5 meaning that the two graphs will intersect at that point.

To the best of my knowledge, that's the only way that equation can be solved!

Richiez:

the most acceptable way to solve this is by graphical method but lets try some mathematical manipulation

X^2 = 2^x ....................(1)
taking log of both sides;
logX^2 = log2^x
2logX =Xlog2 .................(2)
NOTE
in cases like eqn(2) in which the base number on one side of the eqn is similar to the coefficient on the other side
since R.H.S = L.H.S
it implies base number on R.H.S = base number on L.H.S
similarly, coeficient on R.H.S = coeficcient on L.H.S

clearly, X=2

doubleDx:

Take a range for the value of x (eg from -2 to 5) and create a table of values for x^2 and 2^x, then plot these two graphs on the same plot. And they will intersect at x = 2 and x = 4 also at x = -0.7...something. And that would be the solution to your question!

nice.one:
wow! i really missed out on this maths frenzy maths is so fun that it became a past time back then in school. right now am just wallowing in nostalgia of the abstract/complex maths i did during my MSc in control systems engineering.i would love to be part of this but right now am way 2busy. i hail all the guru that is making things happen. maybe i will be recommending you guys for the Melina maths prize . just hv these few contribution to make for; i) X^2=2^X apart from numerical solution (graphical, etc) it can also be solved by differentiating twice and solving for X ii) 3^X +2^X=5^x this can also be solved by playing around diff.

sounds like a nice idea, but pls can u post the solution to d first question by using the method of differentiation you recommended

Gud job people!

doubleDx: Gud job people!

double dy/dx

You guys should shed light on the basic techniques of Vedic Maths.Thanks.

Richiez:

double dy/dx

Lol General Richiez morning bruv!

Richiez:

sounds like a nice idea, but pls can u post the solution to d first question by using the method of differentiation you recommended

I'd like to see that method too. But it seem like differentiating the equation twice makes it more complex. Well, whatever works! I'm ready to learn.

@nice.one, would you mind posting the solution here so we can learn from it? Thank you!

Ghettoguru:

Bless you sir. Thanks a bunch!

oboy that doubledy/dx guy na wizard of first order.......in short, you don know maths pass my maths professor. pls doublex which school did you graduate from? This your calculations are superb.
I tip my hat down to you sir..........

Tushkid74: You guys should shed light on the basic techniques of Vedic Maths.Thanks.

vedic maths!...i can remember when one of my lecturers applied one of the vedic maths trick in the class. we thought he was a wizard until he told us the trick he used.
vedic maths is just based on simple math tricks. for example; 25 * 11
first we have to separate 2 & 5 that is; 2 5
next, we add 2+5=7 and place the result between 2&5, that is; 275
hence, 25 * 11 = 275

TO ALL THE MATHS GURUS:
I doff my heart for your sagacity in dismantling mathematics problems.
MY CASE: A student(newly-admitted and yet to resume) of OAU in the department of ACCOUNTING. I want to use this opportunity to solicit your support in helping me solve any mathematical problem I encounter in the course of my academic work.
May GOD bless and support you in all your endeavours.THANKS.

TOSIN ACCA: TO ALL THE MATHS GURUS:
I doff my heart for your sagacity in dismantling mathematics problems.
MY CASE: A student(newly-admitted and yet to resume) of OAU in the department of ACCOUNTING. I want to use this opportunity to solicit your support in helping me solve any mathematical problem I encounter in the course of my academic work.
May GOD bless and support you in all your endeavours.THANKS.

you are always welcome! but bro you like awoof ooh

Richiez:

sounds like a nice idea, but pls can u post the solution to d first question by using the method of differentiation you recommended

sorry for not responding on time. As i said b/f i hv been very busy.
X^2 = 2^X
diff. twice wrx
2 = 2^X(In2)^2
dividing through by (In2)^2
2/(In2)^2 =2^X
4 =2^X
2^2=2^x
X = 2
since e is an approx. value the approximation (In2)^2 ~ 0.5 was made for easy calculation.
In fact differential/approx. methods of solution of equations forms some of the bases in numerical methods.

nice.one:

sorry for not responding on time. As i said b/f i hv been very busy.
X^2 = 2^X
diff. twice wrx
2 = 2^X(In2)^2
dividing through by (In2)^2
2/(In2)^2 =2^X
4 =2^X
2^2=2^x
X = 2
since e is an approx. value the approximation (In2)^2 ~ 0.5 was made for easy calculation.
In fact differential/approx. methods of solution of equations forms some of the bases in numerical methods.

Okay that's a wise approximation sha

nice.one:

sorry for not responding on time. As i said b/f i hv been very busy.
X^2 = 2^X
diff. twice wrx
2 = 2^X(In2)^2
dividing through by (In2)^2
2/(In2)^2 =2^X
4 =2^X
2^2=2^x
X = 2
since e is an approx. value the approximation (In2)^2 ~ 0.5 was made for easy calculation.
In fact differential/approx. methods of solution of equations forms some of the bases in numerical methods.

ok

topmostg:
oboy that doubledy/dx guy na wizard of first order.......in short, you don know maths pass my maths professor. pls doublex which school did you graduate from? This your calculations are superb.
I tip my hat down to you sir..........

Lol that sounds funny. Thanks anyway, with contributions from math Generals like richiez the op, osita, biolabee, and others, we are good to go! @Ghettoguru, good job!

Richiez:
vedic maths!...i can remember when one of my lecturers applied one of the vedic maths trick in the class. we thought he was a wizard until he told us the trick he used.
vedic maths is just based on simple math tricks. for example; 25 * 11
first we have to separate 2 & 5 that is; 2 5
next, we add 2+5=7 and place the result between 2&5, that is; 275
hence, 25 * 11 = 275

Thanxs man.

Tushkid74:
Thanxs man.

You're welcome, i'll post more vedic maths tricks here as soon as i can lay my hands on them

Na dem b dis
Prove by induction that for any two nos a & b, & for any nEN that
(a+b)^n = a^n + na^(n-1)b + [n(n-1)/2!]a^(n-2)b^(2) + ...+ [n!/(n-k)!k!]a^(n-k)b^k + ... + b^(k)


2. prove d existence theorem of laplace transform
3. show L[f"(t)] = s^2F(s) - sf(0) - f'(0)
4. using the methods of contour intergration & convolution theorem, evaluate
L^-1{1/(s+1)(s^2+1)} &
L^-1{1/(s-2)(s-1)^2}

yungryce: Na dem b dis
Prove by induction that for any two nos a & b, & for any nEN that
(a+b)^n = a^n + na^(n-1)b + [n(n-1)/2!]a^(n-2)b^(2) + ...+ [n!/(n-k)!k!]a^(n-k)b^k + ... + b^(k)


2. prove d existence theorem of laplace transform
3. show L[f"(t)] = s^2F(s) - sf(0) - f'(0)
4. using the methods of contour intergration & convolution theorem, evaluate
L^-1{1/(s+1)(s^2+1)} &
L^-1{1/(s-2)(s-1)^2}

Good questions....

@youngryce, ur questions carry weight oh, but as usual, i'l get the solutions

Richiez: @youngryce, ur questions carry weight oh, but as usual, i'l get the solutions

na so we see am o. d man jst wake one morning carry 50 questns hammer us

I wish

paranorman:
Verily,verily i say unto u,al that thou...

Biblical allusion...