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2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } - Education (14) - Nairaland

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Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by monerozi5590: 12:06pm On May 13, 2016
thankyouJesus:
Good morning all, I was impressed by the solution provided by you guys, keep it. God will water your bread.
Work.
In ordinary meaning, work refers to any kind of physical or mental activity. But in physics, work is always associated with movement. Thus, work is said to be done if a force applied makes the object to move a distance in the direction of the applied force.
Work is defined as the product of force and perpendicular distance in the direction of the applied force. It is denoted by w, measured in Joule and a scaler quantity.
Mathematically;
work = force X distance
w = f X s
since, force = mass X acceleration
work = m X a X s.


Example; A crane lifts a load of 2kg very slowly through a vertical distance of 100cm. Calculate the workdone against gravity if g = 10m/s2.
Solution;
load=2kg
s=100cm=1m
a=g=10m/s2.
Workdone=F X S
w=mas
w=2 X 10 X 1
w=20J.
work can also be defined as energy used .....
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by thankyouJesus(m): 1:02pm On May 13, 2016
monerozi5590:
work can also be defined as energy used .....
Welcome
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by mathefaro(m): 4:01pm On May 13, 2016
monerozi5590:
work can also be defined as energy used .....
incomplete
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by seunwen2(m): 11:30am On May 25, 2016
I have a question hoping to see the solution soonest
A capillary tube of radius 5.0 × 10-5 m is dipped vertically into water contained in a trough. If the surface tension of water is 0.073 Nm-1 and the angle of contact between water and the material of the tube is negligible, determine how high the water will rise in the tube above the surface of the water in the trough. Density of water = 1.0 × 10^3 kgm-3, g = 10 ms-2]
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by mukapaul022: 10:10pm On Oct 22, 2016
H=2Tcosø/prg
Since cosø is negligible it is 1
H=2*0.073*1/1.0 × 10^3 * 5.0 × 10-5*10
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by kemieve: 9:10am On Dec 13, 2016
A battery of e.m. f 12v and internal resistance 1. 5 ohms is connected to an external resistor of resistance 3ohms. calculate the current flowing in the circuit. calc the pd across the 3 ohms resistor and the internal resistance. calc the terminal voltage of the battery.
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by kemieve: 9:15am On Dec 13, 2016
A body of mass of 20kg appears to have a mass of 13kg in oil and 12kg in water. what is the relative density of the oil?
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by mathefaro(m): 8:55pm On Dec 13, 2016
kemieve:
A body of mass of 20kg appears to have a mass of 13kg in oil and 12kg in water. what is the relative density of the oil?
Relative density of liquid x = Upthrust in liquid x/Upthrust in water
Rd = (Wair - Wliquid)/(Wair - Wwater)
(20 - 13)/(20 - 12) = 7/8
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by mathefaro(m): 8:57pm On Dec 13, 2016
kemieve:
A battery of e.m. f 12v and internal resistance 1. 5 ohms is connected to an external resistor of resistance 3ohms. calculate the current flowing in the circuit. calc the pd across the 3 ohms resistor and the internal resistance. calc the terminal voltage of the battery.
Emf = V + Ir; where V is the terminal voltage, r = internal resistance, R = external resistance
E = IR + Ir.
You can finish it if from here
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Donpre(m): 3:45pm On Dec 14, 2016
Guys, I was just flipping through my textbook's pages and the formula for maximum height of a projectile caught my attention

The formula is H = U²sin²O/2g

sin²O gives a math error... in fact sin² doesn't make sense, please someone should put me through, how do I find the square of sin
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by mathefaro(m): 6:13pm On Dec 14, 2016
Donpre:
Guys, I was just flipping through my textbook's pages and the formula for maximum height of a projectile caught my attention

The formula is H = U²sin²O/2g

sin²O gives a math error... in fact sin² doesn't make sense, please someone should put me through, how do I find the square of sin
Ok, here is it
Sin²@ = (Sin@)²
For example, if @=30°
Sin²30 = (Sin30)² = (0.5)² = 0.25
I hope you got that
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Donpre(m): 10:16pm On Dec 14, 2016
mathefaro:
Ok, here is it Sin²@ = (Sin@)² For example, if @=30° Sin²30 = (Sin30)² = (0.5)² = 0.25 I hope you got that
yea I did... thanks a lot
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by mathefaro(m): 7:04am On Dec 15, 2016
Donpre:

yea I did... thanks a lot
you're welcome
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 5:55pm On May 25, 2018
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