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Nairaland Forum / Nairaland / General / Education / 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } (44554 Views)
Nairaland 2016 Jamb Tutorial Classroon [use Of English Thread] / Nairaland 2016 Jamb Tutorial Classroom [chemistry Thread] / Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] (2) (3) (4)
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Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Ennie123(f): 7:15pm On Feb 24, 2016 |
Please guys help me solve this;the magnification of an object 2cm tall when placed 10cm in front of a plane mirror is? |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by mathefaro(m): 7:40pm On Feb 24, 2016 |
Ennie123:The magnification of any object placed in front of a plane mirror is 1 irrespective of the height of the object or its distance from the mirror since the images formed by a plane mirror are always the same size as their respective objects 1 Like |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Ennie123(f): 8:42pm On Feb 24, 2016 |
mathefaro:Okay...thanks |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 11:37am On Feb 25, 2016 |
mathefaro: |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by freshkid144: 11:40am On Feb 25, 2016 |
help me solve ds question. the pressure of a given mass of gas changes from 200nm to 100nm, while its temperature drops from 400k to 346k. calculate the ratio of the final volume of the gas to its initial volume |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 2:58pm On Feb 25, 2016 |
freshkid144:not totally sure, but here, V1 = initial volume. V2 = final volume from the question: P1 = 200nm = (760mmhg x 200)/101325 = 1.5mmhg. Similarly, P2 = 100nm = (760mmhg x 100)/101325 = 0.75mmhg T1 = 400k, T2 = 346K (P1V1)/T1 = (P2V2)/T2 making V2 and V1 the subjects. I.e rearranging the equation to make ratio P2 to P1 the subject of the formula: V2/V1 = (P1T2)/(P2T1) inserting the values V2/V1 = (1.5 x 346)/( 0.75 x 400) V2/V1 = 519/300 519 : 300 |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by freshkid144: 3:49pm On Feb 25, 2016 |
Geofavor:ur wrong |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Ennie123(f): 3:55pm On Feb 25, 2016 |
Please help me solve this:what quantity of aluminium is deposited when a current of 10A is passed through a solution of an aluminium salt for 1930s? |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Orezy5(m): 4:43pm On Feb 25, 2016 |
Ennie123:Solution Al(aq)--->Al3+ + 3e- M=Eit M=(27 x 10 x 1930)/(96500 x 3) M=521100/289500 M= 1.80g |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Ennie123(f): 5:07pm On Feb 25, 2016 |
Orezy5:Thanks |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Orezy5(m): 6:50pm On Feb 25, 2016 |
Ennie123:You are welcome |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by freshkid144: 7:41pm On Feb 25, 2016 |
freshkid144:the answer, using the formula: PV=RT. where, R=0.082, T1=400k, T2=346k, P1=200Nm, P2=100Nm. solve for V=volume in both Equation(1) n (2) n dn find dia ratio |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 8:50pm On Feb 25, 2016 |
freshkid144:ooops! What does "nm" mean? Type the question correctly. |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by freshkid144: 9:05pm On Feb 25, 2016 |
Geofavor:it means NEWTON PER METRE SQUARE |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 11:04pm On Feb 25, 2016 |
A load is pulled at a uniform speed along a horizontal floor by a rope at 45¤ to the floor. If the force in the rope is 1500N, what is the frictional force on the load? Thankyoujesus, shyneptune, mathefaro, oxytocin, orezy5, etc. |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 11:12pm On Feb 25, 2016 |
Geofavor: Resolving to the horizontal F=fcos $ F=1500 cos 45 F=1060.66 Velocity is constant therefore acceleration =0 And since acceleration is 0 that means that the body did not move... Therefore the applied force must have been counterbalanced by an equal and opposite force called friction. This makes the friction to be equal to the horizontal force. 1060.66N 1 Like |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Oxytocin(m): 6:43pm On Feb 26, 2016 |
Only God knows what I did that the crazy bot banned me from education section yesterday |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 7:23pm On Feb 26, 2016 |
Oxytocin:the 'bot' was scared of your 'Physics prowess' |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Oxytocin(m): 12:47am On Feb 27, 2016 |
ShyNeptune:Lolz |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 1:54pm On Feb 27, 2016 |
Geofavor come and tell us how your exam went oh |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 3:57pm On Feb 27, 2016 |
ShyNeptune:yo! Go and marry your past questions |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 5:23pm On Feb 27, 2016 |
Geofavor:seems you had a good time in the hall |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Orezy5(m): 7:36pm On Feb 27, 2016 |
Geofavor how was ur exam? Especially physics and chemistry? |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Oxytocin(m): 9:54pm On Feb 27, 2016 |
Lol Geofavor.. Gist us how this thing went.. |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by druxy(m): 10:10am On Feb 28, 2016 |
A cell can supply currents of 0.4A and 0.2A through a 4.0
Ohms and 10.0 Ohms resistors respectively. The internal
resistance of the cell is |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by druxy(m): 10:11am On Feb 28, 2016 |
A cell can supply currents of 0.4A and 0.2A through a 4.0
Ohms and 10.0 Ohms resistors respectively. The internal
resistance of the cell is |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by druxy(m): 10:13am On Feb 28, 2016 |
A cell can supply currents of 0.4A and 0.2A through a 4.0
Ohms and 10.0 Ohms resistors respectively. The internal
resistance of the cell is |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by druxy(m): 10:14am On Feb 28, 2016 |
A cell can supply currents of 0.4A and 0.2A through a 4.0
Ohms and 10.0 Ohms resistors respectively. The internal
resistance of the cell is |
Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 10:44am On Feb 28, 2016 |
druxy:2 ohms |
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