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Nairaland Forum / Nairaland / General / Education / Can Someone Solve This Polynomial For Me X^4+3x^3+8x^2+10x+8=0 (444 Views)
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Can Someone Solve This Polynomial For Me X^4+3x^3+8x^2+10x+8=0 by ostechno(m): 2:39pm On Dec 10, 2016 |
1. x^4+3x^3+8x^2+10x+8=0 |
Re: Can Someone Solve This Polynomial For Me X^4+3x^3+8x^2+10x+8=0 by Kowor(f): 3:27pm On Dec 10, 2016 |
forward it to math section. |
Re: Can Someone Solve This Polynomial For Me X^4+3x^3+8x^2+10x+8=0 by Akious2k2(m): 4:53pm On Dec 10, 2016 |
ostechno:Mr Oga, use Remainder Rule, Substitute x=1, -1, 2, -1, etc till u get 0 (Zero); Oya, If x=1, 1+27+64+10+8 If x=-1 1-27+64-10+8 Assuming u got 0 when x=k, den (x-k) is a factor Assuming u got 0 when x=-k, den (x+k) is a factor From there, all u need do is to divide that expression by your (x+k) or (x-k) After dividing, u will b left with a polynomial starting with d power of 3 (Note dat there will b no remainder since (x+k) or (x-K) is a factor) Repeat d step again from Substitute x=1, -1, 2, -1, etc till u get 0 (Zero); Assuming u got 0 when x=k, den (x-k) is a factor Assuming u got 0 when x=-k, den (x+k) is a factor From there, all u need do is to divide that expression by your (x+k) or (x-k) After dividing, u will b left with a polynomial starting with d power of 2 (Note dat there will b no remainder since (x+k) or (x-K) is a factor) Then u can solve d rest (Quadratic Equation) like we were taught in secondary school... Cheers |
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