rhydex247:
Solve dis.
1. Electric vector E of an
electromagnetic wave in a free space
is given by Ex=Ez=0, and Ey=Acosw
(t- z/c). By using the maxwell's
equation for a free space, determine
the expression for the components of
H.

Eng. Tino:
fairplay award goes to........nigerian supporters
best coach too...................stephen keshi
most promising talent.................kelechi iheneacho

Justeenaleo: That's how d writer sees it
I cud bet one half of my asss,these ppl u mention r dying inside for sumone to cuddle
Romantic relationship in ma perspective could b a source of motivation wen it comes to finance,if u love sumone u'd not wnt to b a liability,u'd go as far as workin double to support each oda.....
In short y I dey waste time,......if u r a human no matter how u see it,u'd always long for romance
Ogwu ka oham na onu

Ayomide002: [color=#000099][/color].y=(x^2lnx)/sinx...find dy/dx

Mr Calculus: plz i need solutions@my generals:
.
(1).if x=Intan(¥/2) and y=tan¥-¥,prove dat d^2y/dx^2=tan^2¥sin¥(cos¥+2sec¥).
(2).if y=[x+root(1+x^2)]^(3/2),
show dat 4(1+x^2)d^2y/dx^2+4xdy/dx-9y=0.
answers will b really appreciated

Humphrey77: GOOD ! IT CAN ALSO BE OF THE FORM a raise to power log x (base 16) which is equalvent as x . so clearly a is 16

smurfy:

Here goes...

Y = x^x^x
y = (x^x)^x
Let u = x^x
Take log of both sides:
log(u) = log(x^x)
log(u) = xlogx
d/dx[log(u)] = d/dx(xlogx)
1/u(du/dx) = logx + 1
du/dx = u(logx + 1)
du/dx = (x^x)(logx + 1)

Recall that y = u^x
y = u^x
logy = log(u^x)
logy = xlog(u)
d/du(logy) = d/du[xlog(u)]
dy/du(1/y) = x/u
dy/du = xy/u
dy/du = x(x^x^x)/(x^x)

Now, dy/dx = dy/du * du/dx

dy/dx = x(x^x^x)/(x^x) * (x^x)(logx + 1)

dy/dx = x(x^x^x) * (logx + 1)

benbuks: If (logx _(4))^2 =(logx_(2) )(log a_(x) , find a

indoorlove: Log3^x+Logx^3=10/3. Guru in the house, help me with above question

smurfy:

Master? Why you dey fall my hand nah? I be your boy o

I used Microsoft Maths, SIR.

smurfy:

Here goes...

cot@ = cos@/sin@ and sec@ = 1/cos@

So, cot@ + sec@ = 5 becomes
cos@/sin@ + 1/cos@ = 5

Multiply through by sin@cos@, the LCM:

cos^2@ + sin@ = 5sin@cos@

cos^2@ = sin@(5cos@ - 1)

Square both sides to change the sine to cosine:

cos^4@ = sin^2@(5cos@ - 1)^2

cos^4@ = (1 - cos^2@)(25cos^2@ - 10cos@ + 1)

Open brackets to get:

26cos^4@ - 10cos^3@ - 24cos^2@ + 10cos@ - 1 = 0

The equation above is comparable to
26x^4 - 10x^3 - 24x^2 + 10x - 1 = 0

So, cos@ = -0.9865, 0.2089, 0.9699

@Generals

Is there a more novel way of tackling this question? I'd like to know, please.

benbuks: Am working as a computer operator in a company,my manager general, jackpot ask me to creat a 5-digit password for one our agents, such that
1. the square root of the first is the second
2. The second is 5 more than the third
3.the third and the forth are consecutive even and their sum is 10
4. The sum of the whole digits is 30

if i dont creat the right password i might lose my job, u kw my madam, na no nonsense woman o abeg help me create this password...

Humphrey77: sin2x+sinx is equal to 1 we know that sin2x is equal to 2sinxcosx. clearly; we have 2sinxcosx +sinx equal to 1 . so let sinx equal to y; by subtitution into

sin2x + sinx equal to 1 we obtain the equation: 4y"4-3y"2-2y+1 equal to zero ; by solving for y we obtain y equal to 1; clearly recall that sinx is equal to y so we have x eq
ual to arcsin(1) we have x equal to 90 so x is equal to 90

Humphrey77: if 3+5 qual 8 prove that 1+1 equal 2

Fetus: Halo peeps..kindly solve dis showin d workins....(1) find the equation of the tangent and Normal @ any point on the parabola x=6t, y=3t^2.....(2)

factorial1: Play with the questions below:
1. If the radius of a sphere is increased from 10cm to 10.1cm, what is the approximate increase in the surface area?

2. The height of a cylinder is 10cm and its radius is 4cm. Find the approximate increase in volume when the radius increases to 4.02cm

3. An error of 3% is made in measuring the radius of a sphere. Find the percentage error in volume?

4. The side of a square is 5cm. How much will the area of the square increase when the side expands by 0.01cm? And lastly

5. If x=tany; find dy/dx?

factorial1: Ok, here is the solution

If all six digits are used and the number is to be even, the last(right hand) digits must be either 0, 2 or 4 which gives 3 choices. When this's is done, there are 4 choices for the first digit, 3 for the 2nd, 2 for the third and 1 for the forth digit. So, we av 4 x 3 x 2 x 1 x3 = 62 even numbers using all five digits. Now, if all five digits are used and the number is to be even, the last digit cannot be 1, and either 0, 2 or 4 has already been used: therefore, der are 2 choices for the first, for the 2nd digits der are now 2 choices, 1 for d third n' 1 4 the forth= 2 x 2 x 1 x 1=4. Therefore the total num. of even numbers is 4+ 62= 66. Hope I'm correct sha...? coz the qt is somhw confusing to me seeing 0(zero) der