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Phones / Re: Pls,advice Me... by Calculusfx: 7:19am On Nov 04, 2013 |
Royver: It depends. Is he bigger physically? Are you into violence? Or would you rather let things go? How sure are you that he took it? Do you believe in negative prayers?.thank you very much my brother,i understand everything you said,i decided to let it go,but some people who know the value of what the memory card contains are ready to fight for it with their lives coz the guy is a cultist....i'm confused and the only thing he can use on it is songs,even not all of it coz i have about 650 songs on it.....i love your advise bro |
Phones / Pls,advice Me... by Calculusfx: 8:49am On Nov 03, 2013 |
My memory card which comprises many vital things was stolen by a guy....though i didn't see him when he took it,but i knew he was the one who took it...what can i do? |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 6:44am On Nov 01, 2013 |
Hmmmmm Mbahchiboy: still pending.....plz i need answers to dis...s=a(r^n-1)/(r-1)...s(r-1)=a(r^n-1)...sr-s=ar^n-a...sr-ar^n=s-a...r{s-ar^(n-1)}=s-a....but don't forget that ar^(n-1)=nth term of a gp...r(s-nth)=s-a...then r=(s-a)/(s-nth)....i guess that's the solution to the problem...though the last term wasn't specified in the question..... |
Celebrities / Re: Are You Interested In Moderating This Section? by Calculusfx: 7:34pm On Oct 29, 2013 |
I nominate sir tunechi...he will make it to a standard level..believe me |
Education / Re: How To Calculate Quickly And Correctly In Mathematics by Calculusfx: 8:29am On Oct 29, 2013 |
koliks: Gud day 2 d guruus in d auz,can any1 find d integral of dx/e^2x-2e^x...£ represents my integral sign...then £dx/(e^2x-2e^x)...let u be e^x....du=e^xdx...du=udx...dx=du/u...substitute those to get £du/u(u^2-2u)...£du/u^2(u-2)...then let's solve using integration by partial fraction...1/u^2(u-2)=A/u+B/u^2+C/(u-2)...multiply through by u^2(u-2) to get 1=A.u(u-2)+B(u-2)+Cu^2...expand the rhs to get 1=u^2A-2uA+Bu-2B+Cu^2...then 1=(A+C)u^2+(B-2A)u-2B...equate them to give,(A+C)=0,(B-2A)=0 2B=1...then,B=1/2...then 1/2-2A=0...A=1/4...1/4+C=0,then C=-1/4...substitute that,then £1/4u.du+£1/2u^2.du-£1/4(u-2).du...then 1/4lnu-1/2u+1/4ln(u-2)....then lnu^(1/4)+ln(u-2)^(1/4)-1/2u...then ln{u(u-2)}^(1/4)-1/2u...then 1/4ln(e^2x-2e^x)-1/2e^x....i'm rushing in typing,i may be wrong,but i just want you to get the steps...any criticism is allowed |
Education / Re: engineering students forum by Calculusfx: 8:08am On Oct 29, 2013 |
wisemania:...even people have been intimidating me on physics111 before i wrote my postutme...but i never get scared,i'm a mathematician by passion,i shouldn't get afraid of physics...i love this bro...more power and power again...i pray we all succeed...i'm just bothered on td...coz i don't know anything in it,but i believe that if i'm being taught,i will surely comprehend...but i need help of people like you to put me through,i don't know much on mathematics ooo,i just pray i do better...pls,mail me at omoyeleolalekanjacob@gmail.com sir... |
Education / Re: engineering students forum by Calculusfx: 8:00am On Oct 29, 2013 |
wisemania:...hmmm,i love this my brother,but it's not good enough,how would you recommend h.k.dass for a fresher(though i have never seen the textbook before but i know it's advanced oaths textbook),what i can just ask the person to get engineering maths by k.a stroud...but he should not plan of buying pure mathematics by bunday for now...coz bunday wrote his own as if schaum outline series write theirs...the ways you can become a maths guru are 1.get a fundamental math textbooks for now before progressing to higher ones 2.move very close to those who know it(though nobody knows it,it just depends on the aspect one is) 3.get exposed to questions...but the above of all is ur determination and interest on it... |
Education / Re: engineering students forum by Calculusfx: 7:59am On Oct 29, 2013 |
wisemania: |
Education / Re: engineering students forum by Calculusfx: 9:05pm On Oct 27, 2013 |
wisemania:...my brother,i'm uniben mechanical engineer...fresher,and with ur texts.you are an engineer studying in uniben...can you pls help me on some stuffs...like guiding? |
Education / Re: engineering students forum by Calculusfx: 9:01pm On Oct 27, 2013 |
Kendzyma: tnx man...iz td also compulsory der cous I dnt do td in second scul o and I dnt tink I can learn it all by myself at om...my question iz...wen I get der...will I b abl to cope or catch up wit td I mean after seekin elp frm peopl in d scul and with few lectures...iz it posibl to no it by dat...cous I learnt most eng did td rit frm second scul and also waec...we are almost the same bro...i never knew what furthermaths was when i was in sec.school...likewise td...i represent mechanical engineering...UNIBEN...fresher... |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:57pm On Oct 26, 2013 |
Hmmmm |
Education / Re: How To Calculate Quickly And Correctly In Mathematics by Calculusfx: 6:02pm On Oct 16, 2013 |
benbuks: Wow.....my oga at the top...i respect |
Education / Re: How To Calculate Quickly And Correctly In Mathematics by Calculusfx: 5:44pm On Oct 16, 2013 |
Ortarico: Where have my masters been? Pls, save the life of this great thread!...my masters,it's been a while....how maths life Olarewajub: Solve 2^2y + 2 = 33 X 2^y - 8...i think the question is 2^(2y+2)=33*2y-8.... |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 6:31pm On Oct 15, 2013 |
d citizen:...i can see we are the same bro...i'm a mechanical engineer to be,by profession and a mathematician by passion...pls,if you don't mind being my friend,mail me at omoyeleolalekanjacob@gmail.com |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 12:20am On Oct 07, 2013 |
Ortarico:...the polynomial is advance,try and read lodovico ferarri's method for quartic equation...don't ask me,if you don't get it ooo coz the formula is very advance...someone said those who study masters in algebra can be taught the formula...BUT YOU CAN USE IT FOR ANY POLYNOMIAL |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 12:14am On Oct 07, 2013 |
X^4+2x^3+4x^2+8x+16=0 |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 1:14pm On Oct 04, 2013 |
busuyem:...let the number be xy...from the question,we were told that the difference is 1,and the unit digit is greater than the ten digit,which means y-x=1...then y=1+x...EQUATION 1....the question states again that the original question is one more than 5 times the sum of the digits...from xy...the digits are x and y but the original one is 10x+y...assuming 23 which will equal to 10*2+3...then 10x+y=5(x+y)+1...10x+y=5x+5y+1....5x-4y=1...don't forget that y=1+x from equation 1,substitute that to give 5x-4(1+x)=1...5x-4x-4=1...therefore x=5...from equation 1...y=x+1=5+1 to give 6...since the number is xy...then the number is 56... |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 12:55pm On Oct 04, 2013 |
Ortarico:...great master but i guess this is newton-raphson iterative method |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:18pm On Oct 03, 2013 |
benbuks: ....u try bro..bt it seems. U didnt get d question....integrate sqrt[(1 +sqrt(x)]/x..dats d question...re-try......nice 1 dia "calculus(fx)"....y=∫√(1+√x)/x.dx...let √x=a²...x=a^4...dx=4a^3.da...then,∫√(1+a²)/a^4.4a^3da...∫√(1+a²)/a..da...if u²=1+a²...udu=ada...da=udu/a...then ∫u/a*udu/a...∫u²/a².du but u²=1+a²...a²=u²-1...then ∫u²/(u²-1).du...do the division to get...∫1+1/(u²-1).du...from here...let's solve 1/u²-1...resolve to partial fraction,1/u²-1=(A/u-1)+(B/u+1)....1=A(u+1)+B(u-1)...if u=1...A=1/2...and B=-1/2....which gives,1/2(u-1)-1/2(u+1)...then,∫1+1/2(u-1)-1/2(u+1).du...then,{u+1/2ln(u-1)-1/2ln(u+1}...{u+1/2ln(u-1)/(u+1)}+c...don't forget that u²=1+a²...u=√1+a²...don't forget that a²=√x...u=√1+√x...substitute that to the answer to give...{√(1+√x)+(1/2)ln(√1+√x-1)/(√1+√x+1)+c...{√(1+√x)+(1/2)ln(x^1/4)/(√2+√x)+c...i guess.....waiting for better solutions from my generals |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 7:44pm On Oct 03, 2013 |
emmyeuler1: guy u said u got admission to read mechanical engr......but how come u know all this.....did u do any A-LEVEL program?...i'm still your boy master...i haven't done any A-level work ooo.....i pray God helps |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 4:31pm On Oct 03, 2013 |
For the benbuks question....y=∫√1+√x.dx.....let √x be a²...then x=a^4...dx=4a^3da...substitute to give ∫4a^3√1+a².da....let u be 1+a²...du/2a=da...then ∫4a²√u...4∫a²√u but u-1=a²...then,4∫(u-1)√u...4∫(u^3/2)-(u^1/2)...4{[2u^(5/2)]/5-[2u^(3/2)]/3}...8/5.u^(5/2)-8/3.u^(3/2)...but u=a²+1 and a^4=x...substitute those |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:56pm On Oct 03, 2013 |
Odehfamily: 5/12 of a number is subtracted from 3/4 of the number. The positive difference is 7 less than 5/6 of the number. Find the number. plz help me...let the number be x...(3x/4)-(5x/12)=(5x/6)-7...(9x-5x)/12=(5x-42)/6...4x=10x-84...x=14 |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:40pm On Oct 03, 2013 |
busuyem: Help solve dis o-the numerator of a fraction is 5 less than its denominator.if 6 is added to the numerator and 4 to the denominator,the fraction is doubled.what is the fraction?Pls, help me out with this:...let the denominator be x...since the numerator is 5 less than the denominator...then the original fraction is (x-5)/x...but the question continues that 6 is added to the numerator and 4 to the denominator...then (x-5+6)/(x+4)...which is equal to 2 times the original equation{(x-5)/x}...then (x+1)/(x+4)=2(x-5)/x...multiply through by x(x+4){which is the same as cross multiplication} to give x(x+1)=2(x-5)(x+4)...x^2+x=2x^2-2x-40...x^2-3x-40....x=8 or -5...since the original equation is (x-5)/x...substitute 8 which gives 3/8 OR substitute -5 which gives 2 |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:27pm On Oct 03, 2013 |
d citizen:...y=x^x^x^x^x to infinity...which gives y={x^(x^4)}^infinity....but x^4*infinity=infinity...then,y=x^infinity...dy/dx=infinity.x^infinity-1...dy/dx=infinity.x^infinity...since infinity-1=infinity...then dy/dx=infinity... |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:13pm On Oct 03, 2013 |
Fetus: X+y =5...it's obvious that the answer is (3,2) or (3,2) as (x,y)...but if it's of no simple root...use newton raphson method...that x'=x-f(x)/f'(x)...i also heard that the great newton was unable to solve the question |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 2:10pm On Sep 25, 2013 |
2004^2004 |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:06am On Sep 25, 2013 |
rhydex 247: 1. Solve the equation. (x-1)^4+(x+3)^4=82....(3)...x²+xy+y²=84...(i) and x+√xy+y=14...(ii)from (ii).x+y-14=√xy...square both sides...(x+y-14)²=xy...then x²+2xy+y²-28x-28y+196=xy...then x²+2xy-xy+y²-28x-28y+196=0...x²+xy+y²-28x-28y+196...don't forget that from (i)x²+xy+y²=84...substitute that to give...84-28x-28y+196=0...28x+28y=280...divide through by 28...x+y=10...{*}...don't forget that x²+y²=(x+y)²-2xy...substitute that to (i)...(x+y)²-2xy+xy=84...(x+y)²-xy=84 from (*)...x+y=10...i.e...100-xy=84...xy=16...(*')...taking * and *' x+y=10 and xy=16...solve simultaneously to give x=2,y=8 OR x=8,y=2...PLS MY GURUS,IF YOU DON'T UNDERSTAND MY EXPLANATIONS,KINDLY TELL ME TO MAKE MY EXPLANATIONS CLEAR...in my own respective,i think this thread is not for teens... |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:43pm On Sep 24, 2013 |
rhydex 247: 1. Solve the equation. (x-1)^4+(x+3)^4=82....(1)...(x-1)^4+(x+3)^4=82...let {a be x-1}...then x+3=a+4...then a^4+(a+4)^4=82...expand to give...2a^4+16a^3+96a^2+256=82...divide through by 2...a^4+8a^3+48a^2+128a+87=0......solve the polynomial to give (a+1)(a+3)(a^2+4a+29)=0...a=-1 and -3...not that a^2+4a+29=0 gives imaginary number.....don't forget that x-1=a....when a=-1 then x=-1+1=0...when a=-3...x-1=-3...x=-3+1=-2....therefore x=0 or -2 |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 7:56pm On Sep 24, 2013 |
jackpot: Transform "7^sin x" to "e^(sin x ln 7)"....try to show humility sister...i could remember a question benbuks posted,and you asked him not to post simple question again...why can't you solve this,you are just using approximate method...Try to know this that:THERE'S NO MATHS GURU...you can just know up to the level you are and the aspect you are studying......WELL SHA,you tried... 1 Like |
Education / Re: How To Calculate Quickly And Correctly In Mathematics by Calculusfx: 8:42pm On Sep 22, 2013 |
The are some numbers that there factors expect themselves are added up to them...e.g...6 with factors 1,2,3 and 6...without 6,the others are added to 6.....then 28 with factors 1,2,4,7,14and28,without 28...the others are added to 28...find the fifth number that can exhibit this |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:33pm On Sep 22, 2013 |
Sir-Tunechi:...got you bro...thank you very much...that's arithmetric mean |
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:33pm On Sep 22, 2013 |
Kudos to everybody here |
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