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Phones / Re: Pls,advice Me... by Calculusfx: 7:19am On Nov 04, 2013
Royver: It depends. Is he bigger physically? Are you into violence? Or would you rather let things go? How sure are you that he took it? Do you believe in negative prayers?
Logic indicates that you confront him about it. Dont accuse him of stealing it, just pointedly let him know that it is missing. Tell him you have valuable information on it and you'll be really pissed if its not found. Tell him to 'help' you search for it. That will give him the option of conjuring it out of somewhere and saying he 'found' it. If he proves stubborn however, you either let it go to catch him another time or you get physical and search thru his things.
Those are the options I can think of.
.thank you very much my brother,i understand everything you said,i decided to let it go,but some people who know the value of what the memory card contains are ready to fight for it with their lives coz the guy is a cultist....i'm confused and the only thing he can use on it is songs,even not all of it coz i have about 650 songs on it.....i love your advise bro
Phones / Pls,advice Me... by Calculusfx: 8:49am On Nov 03, 2013
My memory card which comprises many vital things was stolen by a guy....though i didn't see him when he took it,but i knew he was the one who took it...what can i do?
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 6:44am On Nov 01, 2013
Hmmmmm
Mbahchiboy: still pending.....plz i need answers to dis
...s=a(r^n-1)/(r-1)...s(r-1)=a(r^n-1)...sr-s=ar^n-a...sr-ar^n=s-a...r{s-ar^(n-1)}=s-a....but don't forget that ar^(n-1)=nth term of a gp...r(s-nth)=s-a...then r=(s-a)/(s-nth)....i guess that's the solution to the problem...though the last term wasn't specified in the question.....
Celebrities / Re: Are You Interested In Moderating This Section? by Calculusfx: 7:34pm On Oct 29, 2013
I nominate sir tunechi...he will make it to a standard level..believe me
Education / Re: How To Calculate Quickly And Correctly In Mathematics by Calculusfx: 8:29am On Oct 29, 2013
koliks: Gud day 2 d guruus in d auz,can any1 find d integral of dx/e^2x-2e^x
...£ represents my integral sign...then £dx/(e^2x-2e^x)...let u be e^x....du=e^xdx...du=udx...dx=du/u...substitute those to get £du/u(u^2-2u)...£du/u^2(u-2)...then let's solve using integration by partial fraction...1/u^2(u-2)=A/u+B/u^2+C/(u-2)...multiply through by u^2(u-2) to get 1=A.u(u-2)+B(u-2)+Cu^2...expand the rhs to get 1=u^2A-2uA+Bu-2B+Cu^2...then 1=(A+C)u^2+(B-2A)u-2B...equate them to give,(A+C)=0,(B-2A)=0 2B=1...then,B=1/2...then 1/2-2A=0...A=1/4...1/4+C=0,then C=-1/4...substitute that,then £1/4u.du+£1/2u^2.du-£1/4(u-2).du...then 1/4lnu-1/2u+1/4ln(u-2)....then lnu^(1/4)+ln(u-2)^(1/4)-1/2u...then ln{u(u-2)}^(1/4)-1/2u...then 1/4ln(e^2x-2e^x)-1/2e^x....i'm rushing in typing,i may be wrong,but i just want you to get the steps...any criticism is allowed
Education / Re: engineering students forum by Calculusfx: 8:08am On Oct 29, 2013
wisemania:
from ur username its like uve got a gr8 deal of calculus forshesprin goin well 4u...kip d spirit high,solve as mch probs u encounter..ppls du hype phy111 greatly but no fear coz men dey nack am A wella...juz try n get ist semester's txts ,read and solve d exercises dat follow suit...try n get PQ as well..infact u dnt av 2 stress ur slf dat mch,coz wen u rezume u go c enof materials tire ...*my2cents*
...even people have been intimidating me on physics111 before i wrote my postutme...but i never get scared,i'm a mathematician by passion,i shouldn't get afraid of physics...i love this bro...more power and power again...i pray we all succeed...i'm just bothered on td...coz i don't know anything in it,but i believe that if i'm being taught,i will surely comprehend...but i need help of people like you to put me through,i don't know much on mathematics ooo,i just pray i do better...pls,mail me at omoyeleolalekanjacob@gmail.com sir...
Education / Re: engineering students forum by Calculusfx: 8:00am On Oct 29, 2013
wisemania:
dnt be afraid bro,d 2ruth is wen u get der ud definately cope,but ill advice strongly dat u get a gud maths txt bk ryt about 4rm any wr possible(e.g ordinary engine maths by HK dass/business maths/pure maths by bunday)...eida of dis books will put u 2ru f.maths,coz no lecurer will explain in details 2u,dey will asume u alredy have d basics wif u...just get bunday @least,it will du u real gud,and dnt under-estimate engine math by stroud its also a great deal 4 beginners ,well equiped wif all u nid 2 surpass mth110, it also treats complex number 2 d reqired level....try dem out and ur maths life will neva remain d xame again.. *1 10v3*
...hmmm,i love this my brother,but it's not good enough,how would you recommend h.k.dass for a fresher(though i have never seen the textbook before but i know it's advanced oaths textbook),what i can just ask the person to get engineering maths by k.a stroud...but he should not plan of buying pure mathematics by bunday for now...coz bunday wrote his own as if schaum outline series write theirs...the ways you can become a maths guru are
1.get a fundamental math textbooks for now before progressing to higher ones
2.move very close to those who know it(though nobody knows it,it just depends on the aspect one is)
3.get exposed to questions...but the above of all is ur determination and interest on it...
Education / Re: engineering students forum by Calculusfx: 7:59am On Oct 29, 2013
wisemania:
dnt be afraid bro,d 2ruth is wen u get der ud definately cope,but ill advice strongly dat u get a gud maths txt bk ryt about 4rm any wr possible(e.g ordinary engine maths by HK dass/business maths/pure maths by bunday)...eida of dis books will put u 2ru f.maths,coz no lecurer will explain in details 2u,dey will asume u alredy have d basics wif u...just get bunday @least,it will du u real gud,and dnt under-estimate engine math by stroud its also a great deal 4 beginners ,well equiped wif all u nid 2 surpass mth110, it also treats complex number 2 d reqired level....try dem out and ur maths life will neva remain d xame again.. *1 10v3*
Education / Re: engineering students forum by Calculusfx: 9:05pm On Oct 27, 2013
wisemania:
welcome onboard oil-man...u cn strt reading now-mth110(algebra n element trig mixed wif complex num),mth112(calculus)....diz r 4d ist semester....den mth123 and mth125(ODE)....strt wit d 1st 2mths...its not diff if u can only study hrd...make frends wif sm1 dat haz surpassed dat level in order 2 gain access 2 d materials ud be nidin...*ugo enjoy pet engine*
...my brother,i'm uniben mechanical engineer...fresher,and with ur texts.you are an engineer studying in uniben...can you pls help me on some stuffs...like guiding?
Education / Re: engineering students forum by Calculusfx: 9:01pm On Oct 27, 2013
Kendzyma: tnx man...iz td also compulsory der cous I dnt do td in second scul o and I dnt tink I can learn it all by myself at om...my question iz...wen I get der...will I b abl to cope or catch up wit td I mean after seekin elp frm peopl in d scul and with few lectures...iz it posibl to no it by dat...cous I learnt most eng did td rit frm second scul and also waec
...we are almost the same bro...i never knew what furthermaths was when i was in sec.school...likewise td...i represent mechanical engineering...UNIBEN...fresher...
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:57pm On Oct 26, 2013
Hmmmm
Education / Re: How To Calculate Quickly And Correctly In Mathematics by Calculusfx: 6:02pm On Oct 16, 2013
benbuks: Wow.
....my oga at the top...i respect
Education / Re: How To Calculate Quickly And Correctly In Mathematics by Calculusfx: 5:44pm On Oct 16, 2013
Ortarico: Where have my masters been? Pls, save the life of this great thread!
...my masters,it's been a while....how maths life
Olarewajub: Solve 2^2y + 2 = 33 X 2^y - 8
...i think the question is 2^(2y+2)=33*2y-8....
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 6:31pm On Oct 15, 2013
d citizen:
@alpha, u are not serious

Am a mechanical engineer by profession and a mathematician by passion
...i can see we are the same bro...i'm a mechanical engineer to be,by profession and a mathematician by passion...pls,if you don't mind being my friend,mail me at omoyeleolalekanjacob@gmail.com
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 12:20am On Oct 07, 2013
Ortarico:

You seem to be right sha. I did it by inspection. It's better if one leaves it as (x - 2) (x^4 + 2x^3 + 4x^2 + 8x + 16) then.
...the polynomial is advance,try and read lodovico ferarri's method for quartic equation...don't ask me,if you don't get it ooo coz the formula is very advance...someone said those who study masters in algebra can be taught the formula...BUT YOU CAN USE IT FOR ANY POLYNOMIAL
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 12:14am On Oct 07, 2013
X^4+2x^3+4x^2+8x+16=0
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 1:14pm On Oct 04, 2013
busuyem:

No solution yet?
...let the number be xy...from the question,we were told that the difference is 1,and the unit digit is greater than the ten digit,which means y-x=1...then y=1+x...EQUATION 1....the question states again that the original question is one more than 5 times the sum of the digits...from xy...the digits are x and y but the original one is 10x+y...assuming 23 which will equal to 10*2+3...then 10x+y=5(x+y)+1...10x+y=5x+5y+1....5x-4y=1...don't forget that y=1+x from equation 1,substitute that to give 5x-4(1+x)=1...5x-4x-4=1...therefore x=5...from equation 1...y=x+1=5+1 to give 6...since the number is xy...then the number is 56...
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 12:55pm On Oct 04, 2013
Ortarico:

Even nondeterministic polynomial (NP) method can be used.
x = x1 - f(x1)/f'(x1)

3^x + 4^x = 5^x
3^x + 4^x - 5^x = 0
f(x) = 3^x + 4^x - 5^x
from polynomial:
f(x1) = 3^x + 4^x - 5^x
let x1 = 2
f(2) = 3^2 + 4^2 - 5^2
f(2) = 9 + 16 - 25
f(2) = 0
:. x = 2 is a factor

f'(x) = 3^xIn3 + 4^xIn4 - 5^xIn5
f'(2) = 9In3 + 16In4 - 25In5
f'(2) = 9.89 + 22.18 - 40.24
f'(2) = -8.17

i.e x1 = 2, f(2) = 0 and f'(2) = -8.17. . . .substituting into the formula above:
x = 2 - 0/-8.17
x = 2 + 0
x = 2
...great master but i guess this is newton-raphson iterative method
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:18pm On Oct 03, 2013
benbuks: ....u try bro..bt it seems. U didnt get d question....integrate sqrt[(1 +sqrt(x)]/x..dats d question...re-try......nice 1 dia "calculus(fx)".
...y=∫√(1+√x)/x.dx...let √x=a²...x=a^4...dx=4a^3.da...then,∫√(1+a²)/a^4.4a^3da...∫√(1+a²)/a..da...if u²=1+a²...udu=ada...da=udu/a...then ∫u/a*udu/a...∫u²/a².du but u²=1+a²...a²=u²-1...then ∫u²/(u²-1).du...do the division to get...∫1+1/(u²-1).du...from here...let's solve 1/u²-1...resolve to partial fraction,1/u²-1=(A/u-1)+(B/u+1)....1=A(u+1)+B(u-1)...if u=1...A=1/2...and B=-1/2....which gives,1/2(u-1)-1/2(u+1)...then,∫1+1/2(u-1)-1/2(u+1).du...then,{u+1/2ln(u-1)-1/2ln(u+1}...{u+1/2ln(u-1)/(u+1)}+c...don't forget that u²=1+a²...u=√1+a²...don't forget that a²=√x...u=√1+√x...substitute that to the answer to give...{√(1+√x)+(1/2)ln(√1+√x-1)/(√1+√x+1)+c...{√(1+√x)+(1/2)ln(x^1/4)/(√2+√x)+c...i guess.....waiting for better solutions from my generals
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 7:44pm On Oct 03, 2013
emmyeuler1: guy u said u got admission to read mechanical engr......but how come u know all this.....did u do any A-LEVEL program?
...i'm still your boy master...i haven't done any A-level work ooo.....i pray God helps
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 4:31pm On Oct 03, 2013
For the benbuks question....y=∫√1+√x.dx.....let √x be a²...then x=a^4...dx=4a^3da...substitute to give ∫4a^3√1+a².da....let u be 1+a²...du/2a=da...then ∫4a²√u...4∫a²√u but u-1=a²...then,4∫(u-1)√u...4∫(u^3/2)-(u^1/2)...4{[2u^(5/2)]/5-[2u^(3/2)]/3}...8/5.u^(5/2)-8/3.u^(3/2)...but u=a²+1 and a^4=x...substitute those
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:56pm On Oct 03, 2013
Odehfamily: 5/12 of a number is subtracted from 3/4 of the number. The positive difference is 7 less than 5/6 of the number. Find the number. plz help me
...let the number be x...(3x/4)-(5x/12)=(5x/6)-7...(9x-5x)/12=(5x-42)/6...4x=10x-84...x=14
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:40pm On Oct 03, 2013
busuyem: Help solve dis o-the numerator of a fraction is 5 less than its denominator.if 6 is added to the numerator and 4 to the denominator,the fraction is doubled.what is the fraction?Pls, help me out with this:

...let the denominator be x...since the numerator is 5 less than the denominator...then the original fraction is (x-5)/x...but the question continues that 6 is added to the numerator and 4 to the denominator...then (x-5+6)/(x+4)...which is equal to 2 times the original equation{(x-5)/x}...then (x+1)/(x+4)=2(x-5)/x...multiply through by x(x+4){which is the same as cross multiplication} to give x(x+1)=2(x-5)(x+4)...x^2+x=2x^2-2x-40...x^2-3x-40....x=8 or -5...since the original equation is (x-5)/x...substitute 8 which gives 3/8 OR substitute -5 which gives 2
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:27pm On Oct 03, 2013
d citizen:
Differentiate y= x^x^x^x^x to infinte with respect to x . I pose dis question to the math general
...y=x^x^x^x^x to infinity...which gives y={x^(x^4)}^infinity....but x^4*infinity=infinity...then,y=x^infinity...dy/dx=infinity.x^infinity-1...dy/dx=infinity.x^infinity...since infinity-1=infinity...then dy/dx=infinity...
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 3:13pm On Oct 03, 2013
Fetus: X+y =5
x^x + y^y=31.......find x and y....
...it's obvious that the answer is (3,2) or (3,2) as (x,y)...but if it's of no simple root...use newton raphson method...that x'=x-f(x)/f'(x)...i also heard that the great newton was unable to solve the question
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 2:10pm On Sep 25, 2013
2004^2004
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:06am On Sep 25, 2013
rhydex 247: 1. Solve the equation. (x-1)^4+(x+3)^4=82.
2. The real numbers a,b,c satisfy a<>b and 2009[a-b]+sqrt(2009)[b-c]+[c-a]=0. Find the value of (c-b)(c-a)/(a-b)^2.
3. Solve the systems of eqn.
x^2+xy+y^2=84...eqn 1 and x+sqrt(xy)+y=14...eqn 2.
...(3)...x²+xy+y²=84...(i) and x+√xy+y=14...(ii)from (ii).x+y-14=√xy...square both sides...(x+y-14)²=xy...then x²+2xy+y²-28x-28y+196=xy...then x²+2xy-xy+y²-28x-28y+196=0...x²+xy+y²-28x-28y+196...don't forget that from (i)x²+xy+y²=84...substitute that to give...84-28x-28y+196=0...28x+28y=280...divide through by 28...x+y=10...{*}...don't forget that x²+y²=(x+y)²-2xy...substitute that to (i)...(x+y)²-2xy+xy=84...(x+y)²-xy=84 from (*)...x+y=10...i.e...100-xy=84...xy=16...(*')...taking * and *' x+y=10 and xy=16...solve simultaneously to give x=2,y=8 OR x=8,y=2...PLS MY GURUS,IF YOU DON'T UNDERSTAND MY EXPLANATIONS,KINDLY TELL ME TO MAKE MY EXPLANATIONS CLEAR...in my own respective,i think this thread is not for teens...
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:43pm On Sep 24, 2013
rhydex 247: 1. Solve the equation. (x-1)^4+(x+3)^4=82.
2. The real numbers a,b,c satisfy a<>b and 2009[a-b]+sqrt(2009)[b-c]+[c-a]=0. Find the value of (c-b)(c-a)/(a-b)^2.
3. Solve the systems of eqn.
x^2+xy+y^2=84...eqn 1 and x+sqrt(xy)+y=14...eqn 2.
...(1)...(x-1)^4+(x+3)^4=82...let {a be x-1}...then x+3=a+4...then a^4+(a+4)^4=82...expand to give...2a^4+16a^3+96a^2+256=82...divide through by 2...a^4+8a^3+48a^2+128a+87=0......solve the polynomial to give (a+1)(a+3)(a^2+4a+29)=0...a=-1 and -3...not that a^2+4a+29=0 gives imaginary number.....don't forget that x-1=a....when a=-1 then x=-1+1=0...when a=-3...x-1=-3...x=-3+1=-2....therefore x=0 or -2
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 7:56pm On Sep 24, 2013
jackpot: Transform "7^sin x" to "e^(sin x ln 7)".

Get the Maclaurin series expansion for the exponential function. e^x =\sum\limits_{k=1}^{\infty} \frac{x^k}{k!}

Replace "x" with "sin x ln 7"

Finally, integrate term by term.

Thats all!
...try to show humility sister...i could remember a question benbuks posted,and you asked him not to post simple question again...why can't you solve this,you are just using approximate method...Try to know this that:THERE'S NO MATHS GURU...you can just know up to the level you are and the aspect you are studying......WELL SHA,you tried...

1 Like

Education / Re: How To Calculate Quickly And Correctly In Mathematics by Calculusfx: 8:42pm On Sep 22, 2013
The are some numbers that there factors expect themselves are added up to them...e.g...6 with factors 1,2,3 and 6...without 6,the others are added to 6.....then 28 with factors 1,2,4,7,14and28,without 28...the others are added to 28...find the fifth number that can exhibit this
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:33pm On Sep 22, 2013
Sir-Tunechi:

if a,b,c,d, z an ap den a+c=2b nd b+d=2c derefore 7+15=2y, y=22/2=11 den x+y=2*7,
x+11=14
x=3. Simple
...got you bro...thank you very much...that's arithmetric mean
Education / Re: Nairaland Mathematics Clinic by Calculusfx: 8:33pm On Sep 22, 2013
Kudos to everybody here

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