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The bearing of A from B is 308.6 deg.

Using cosine and sine rule you will arrive at 306 deg.

You may contact me for any further clarification where necessary.

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The answer is 11 am. So you're very correct. The logic is 50% increase which is 27 mph. This results to 1 hr as time taken to return. Therefore 10 + 1 = 11 am.


Solutions

The bus started at 8am from the bus stand
On getting to it destination, it spent 30mins

So, let's calculate d time it spent on getting to its destination:
Distance to its destination= 27miles
Speed of the bus= 18mph
time?
using d formula:
Speed= distance/time

time= distance/speed
T=27miles/18miles per hr
T= 1.5hr
convert to minutes
T= 1.5*60= 90mins
T= 1hr 30mins
So it spent 1hr 30mins to its destination. then u add it to the 8am. (8am + 1hr 30mins) 9:30 am

So it reaches to its destination at 9:30am

On getting to its destination, it spent 30mins b4 taken off. so, 9:30am + 30 mins = 10am

So it left its destination at 10am

On returning to its stand, it speed increases by 50%(50% fast speed);
So returning increasing speed= 50/100*18mph= 9mph

New speed= 9mph + 18mph= 27mph
Distance = 27miles
time?
time= distance/speed
T=27miles/27mph
T= 1hr

it spent 1hr to get back 2 its stand

Time it reaches back 2 its stand=time it left its destination + time it spent 2 get back 2 its stand

Time = 10am + 1hr = 11am.

Ans= A. 11am








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