Cc Sexykaycee, Prot0n, Mathefaro et al, now will be a good time to come in (my schedules, power supply and other unforeseen circumstances are not favourable).
[Thankyoujesus i need you to teach us more, pls try and use the syllabus. Nice work.]

Thankyoujesus....i appreciate your work and effort you have committed into this forum but I'd like to correct you on something on your tutor concerning acceleration due to gravity on the Earth and that on the moon were you stated that
6g of Earth =g on the moon
...................................................
This should rather be
1/6g of Earth=g on moon
since the Earth is approximately six times bigger than of the moon
...hence an object on the moon should fall slower than that on Earth.

I believe this mistake must have been due to stress,anyways cheers

stanley59:
Thankyoujesus....i appreciate your work and effort you have committed into this forum but I'd like to correct you on something on your tutor concerning acceleration due to gravity on the Earth and that on the moon were you stated that
6g of Earth =g on the moon
...................................................
This should rather be
1/6g of Earth=g on moon
since the Earth is approximately six times bigger than of the moon
...hence an object on the moon should fall slower than that on Earth.

I believe this mistake must have been due to stress,anyways cheers

Correction noted, thank you, it was an oversight.

ThankyouJesus first of all let me thank u for the wonderful work u have done here so far, I really appreciate, God will reward u in a thousand folds In jesus name Amen..

Pls can u write a note on Simple A.C circuit.. Will appreciate it greatly...

Justice28:
ThankyouJesus first of all let me thank u for the wonderful work u have done here so far, I really appreciate, God will reward u in a thousand folds In jesus name Amen..

Pls can u write a note on Simple A.C circuit.. Will appreciate it greatly...

Okay sir, I will do that in bits depending on my schedule.

[b]Simple AC Circuit.
An alternating current changes direction periodically as a result of the changing of the emf. The circuit in which an alternating current flows is called an alternating AC circuit.
Peak Current and Peak Voltage..
The peak current is represented as I_o and peak voltage as V_o.
Mathematically;
I_o=I_rms X root 2.
Similarly;
V_o=V_rms X root 2.
Note; rms (root mean square)current is defined as the steady or direct current which produces the same heating effect per second in a given resistor.

---

Example; Find the peak value of a sinusoidal current when the rms value of the current is 30A.
Solution:
I_rms= 30A.
I_o=I_rms X root2.
I_o=42.43A.

---

Phasor Diagram.
Phasor diagram is the diagram by which AC currents and voltages are represented by a straight line, having definite direction and magnitude.[/b]

Example; a resistance of 40 Ohm, an inductor of 0.2H and a capacitor of 10uF are connected in a series with an AC supply of E=300sin314t. Calculate (a) frequency of AC supply (b) voltage amplitude (c) inductive reactance (d) capacitive reactance (e) impedance.
Solution:
R=40 Ohm.
L=0.2H.
C=10uF=10^-5F.
(a) comparing the equation with;
E=Vsinwt.
W=314.
Recall that, w=2 X pi X f.
F=50Hz.
(b) same as above,
E=300V.
(c) X_L=wL=62.86 Ohm.
(d) X_c=1/wc=318.18 Ohm.
(e) Z²=R²+(X_L-X_c)².
Z=258.43 Ohm.

Justice28:
ThankyouJesus first of all let me thank u for the wonderful work u have done here so far, I really appreciate, God will reward u in a thousand folds In jesus name Amen..

Pls can u write a note on Simple A.C circuit.. Will appreciate it greatly...

Any question or question for "us" to solve?

thankyouJesus:
Any question or question for "us" to solve?

It's clear sir thanks

[quote author=thankyouJesus post=41842894]Pls, teach us about VAPOURS

thankyouJesus:
Good morning all, I want to assume most of you know this basic topics in Physics, lets move to more complex topics. To achieve this, could you drop a topic for me to write on taking into consideration my resumption date in UI.
Cc DebbyChris Oxytocin Geofavor Iceberryose Muhamadnur Orezy5

please sir how do i go about physics and understand it much beta, the reason why i dnt undstand physics is due to my poor attendance of school due to boko haram insurgency in my state. I only attended ss2 skipping ss1 and ss3. I wrote weac and luckily got 9credit.i went to polytechnic but failed in my pre_nd. And know i am putting more effort to pass jamb and go to unive$ty for geology. Please help advice.

thankyouJesus:
[b]Good morning all.
Elasticity.
Elasticity is the ability of a material to regain its original shape or size after deformation. Deformation is elastic if the wire returns to its original position, while it is plastic if it does not return to its original position.
Terms used in elasticity.
1. Elastic limit; Elastic limit is the maximum load (force) which a body can experience and still retain its original size/shape. It can also be defined as the point which Hooke's law is no longer obeyed.
2. Yield point; Yield point is reached when a stretched wire does not return to its original position.
3. Maximum load; When a load is added to a wire that it cannot stand any further increase, it is called maximum load.
4. Breaking point; Breaking point is the point at which the wire breaks away from the original.
Hooke's law.
It states that the force applied to a spring is directly proportional to the extension produced, provided the proportionality limit is not exceeded.
Mathematically;
F ~ E
F = KE
where K is constant (N/m).

---

Example; The extension on a spring when 5g was hung from it was 0.56cm. If Hooke's law is obeyed, what is the extension caused by a load of 20g.
Solution;
F₁=5g
E₁=0.56cm
F₂=20g
E₂=x
F₁/E₁=F₂/E₂.
5/0.56 = 20/x
5x = 0.56 X 20
x = 2.24cm[/b]

pls check dis out...

The total lenght of a spring when a mass of 200g is hung from it's end is 14cm, while it's total lenght is 16cm when a mass of 30kg is hung from the same end. Calculate the unstretched lenght of the spring assuming Hooke's law is obeyed.

bawz012:



pls check dis out...

The total lenght of a spring when a mass of 200g is hung from it's end is 14cm, while it's total lenght is 6cm when a mass of 30kg is hung from the same end. Calculate the unstretched lenght of the spring assuming Hooke's law is obeyed.

This question is a bit illogical because extension is directly proportional to the load so the more the load, the more the extension. In other words, it is impossible to have a total length of 6cm by a mass of 30kg when you have 14cm for just a mass of 200g(0.2kg) on the same spring. So check and rectify the error. However, after correcting the error in the values, you can then use the formula:
F1/(L1 - l) = F2/(L2 - l)
Where F1 and F2 are the weights of the two masses, (L - l) the extension while L1 and L2 represents the total lengths(extended) of the spring when the 2 masses were hung from the end of the spring and l is the original length(unstretched) being requested from the question.

I dnt know that there's a rich thread like this, its a privileged to be here!...To our Teachers and contributors, more grease to your elbows, please dnt relent,
keep on with the good work

Tobiee:
[email] thankyoujesus.. >> A ball of mass 0.15kg is kicked with a horizontal velocity of 50ms-1. If it rebounced with a horizontal velocity of 30ms-1, calculate the impulse of the ball on the wall. [/email]

ft (impulse)= Mv-Mu (change in momentum)
=M(v-u)
=0.15(50--30)
=0.15(80)
=12kgms-1

Ikennablue:


ft (impulse)= Mv-Mu (change in momentum)
=M(v-u)
=0.15(50--30)
=0.15(80)
=12kgms-1

[email] Huh? In the past question it's different. Where did you get -30? [/email]

Tobiee:
[email] thankyoujesus
geofavor
ikennablue >> A body of mass 10kg, moving with velocity of 10ms-1, hit a stationary body and had its direction reversed and velocity changed to 7.5ms-1 in 5seconds. Calculate the force of impact. [/email]

f=mv-mu/t
=m(v-u)/t
=10(7.5--10)/5
=10(17.5)/5
f= 35N.

Tobiee:
[email] Huh? In the past question it's different. Where did you get -30? [/email]

If the ball rebounce, it will be moving to the opposite initial velocity, so its negative. ie (-30)

I have a lot to catch up on

[email] The least possible error encountered when taking measurement with a meter rule is? [/email]

mathefaro:
This question is a bit illogical because extension is directly proportional to the load so the more the load, the more the extension. In other words, it is impossible to have a total length of 6cm by a mass of 30kg when you have 14cm for just a mass of 200g(0.2kg) on the same spring. So check and rectify the error. However, after correcting the error in the values, you can then use the formula:
F1/(L1 - l) = F2/(L2 - l)
Where F1 and F2 are the weights of the two masses, (L - l) the extension while L1 and L2 represents the total lengths(extended) of the spring when the 2 masses were hung from the end of the spring and l is the original length(unstretched) being requested from the question.

16cm ...... corrected

bawz012:



16cm ...... corrected

Do you still need help with the solution?

mathefaro:
Do you still need help with the solution?

Affirmative Sir

That's the link for biology thread.. Interested people should visit


www.nairaland.com/2866679/2016-2017-jamb-biology

enjoying this thread..... a nairalander created a study group on whatsapp.thankujesus I would love if u could help us with physics,08160081746 is d number.those interested would also be added.

bawz012:


Affirmative Sir

Here you have it. Sorry for the late reply

it's been a while here. Thankyoujesus, thank you for your work here.