Oxytocin:
Yhyh.. Sin#=1/98 So from F=Mgsin# Mg(1/98)...Then you solve from there I've actually gotten the ans... Thanks anyway

ShyNeptune:

ques fresco

keypad1:
Please i need english class thread.

Orezy5:
1. A broadcasting station transmits at a frequency of 89.5MHz. What capacitance together with an inductance of 30uH is needed to tune this station?

2. The linear coefficient of expansion of aluminium is 23 x 10^-6oC^-1 and that of iron is 11 x 10^-6oC^-1. The length of an aluminium rod is 0.24 times the length of an iron rod when both are at 0^oC. The temperature of the aluminium rod is increased to 60^oC while that of the iron rod is imcreased to 45^oC. Calculate the ratio of the increase in the length of the aluminium rod to that of the iron rod.

3. A 10.0Kg mass is dragged along a horizontal table by a 60N force. The force is inclined at an angle 30^o to the horizontal, and the coefficient of dynamic friction between the mass and the table is 0.15. Calculate the acceleration of the mass. g=10m/s²

keypad1:
Please i need english class thread.

davidbolton234:
i guess these are oau 2015 pume questions

ShyNeptune:
nice questions...... will solve 'em when I'm home.

Orezy5:

okay, pls endeavour to type out the solutions(if u don't mind)

Orezy5:
1. A broadcasting station transmits at a frequency of 89.5MHz. What capacitance together with an inductance of 30uH is needed to tune this station?

2. The linear coefficient of expansion of aluminium is 23 x 10^-6oC^-1 and that of iron is 11 x 10^-6oC^-1. The length of an aluminium rod is 0.24 times the length of an iron rod when both are at 0^oC. The temperature of the aluminium rod is increased to 60^oC while that of the iron rod is imcreased to 45^oC. Calculate the ratio of the increase in the length of the aluminium rod to that of the iron rod.

3. A 10.0Kg mass is dragged along a horizontal table by a 60N force. The force is inclined at an angle 30^o to the horizontal, and the coefficient of dynamic friction between the mass and the table is 0.15. Calculate the acceleration of the mass. g=10m/s²

Oxytocin:

1)1.05×10^-13F
2)184:275
3)6.67m/s²



Not really sure of no 3 tho


... will try to post workings

ShyNeptune:

Okay, I didn't bother solving the rest since you're sure of them.
I only solved number 3 since you're not too sure and I got 4.146 m/s2 as my answer.......

Oxytocin:

Show your workings and I show mine
Let's juxtapose

Oxytocin:
@Orezy5 No 1

ShyNeptune:

Okay, I didn't bother solving the rest since you're sure of them.
I only solved number 3 since you're not too sure and I got 4.146 m/s2 as my answer.......

Oxytocin:

Show your workings and I show mine
Let's juxtapose

Orezy5:

Thanks bro

ShyNeptune:

i ran through your past posts. And your last jamb score was impressive.
Now im confused, didn't you secure admission last year?

Orezy5:

I did, but i was given another course. I wrote oau's post jamb but fuc.ked up in physics..

ShyNeptune:

Oh.. so sorry bout that... I just hope this year will be a year of jubilation for you and for all of us

Orezy5:

Amen. Thanks for ur concern

ShyNeptune:

It's just a rough work though.

Oxytocin:


Lol.. I don't get you oo

ShyNeptune:

which part?

Oxytocin:

All bro... All the parts

ShyNeptune:

all I did was resolve the applied force into into its horizontal and vertical components.
For the horizontal
Fnet= 60cos30 - Ffriction

For the vertical
60sin60 + N = mg

Where mg= 10×10 = 100

Then I proceeded to look for the acceleration

Oxytocin:

Hmm..... Okkkk
I now get
Thanks bro