Mrphantom99:
1.) Simplify (sqr5+1/sqr5)(sqr5–1/sqr3)

2.)If y= 3x²(x³+1)^½ find dy/dx

3.) solve the inequality
1/3x+5/8>1/2x-2/24 or x/3+5/8>or=x/2-2/24

Mrphantom99:
1.) Simplify (sqr5+1/sqr5)(sqr5–1/sqr3)

timmykaydude:
Profmathsland,I have heard that also....nnamdi1998,has your maths questions been answered?if yes,send me the answer on facebook.

timmykaydude:
nnamdi1998,has your maths questions been answered?.

profmathsland:

Which of them please?

Idenyijoshua:
good evening.
please how do I approach this:
xy=k, where k is a constant.

timmykaydude:
do you mean the mathematics question?

francisdfreak:
How does one solve an equation which has x as a factor or variable on both sides of the equal sign?
An equation like: 2x=4x, find x or 50x^3/2=32x^-1/2. Find x

A well detailed/step by step solution will be greatly appreciated

masperano:


The first is 2x-4x=0 this implies that -2x=0, hence x=0; the second equation can be solved by multiplying both sides of the equation by x^1/2. So you have 50x^2=32; hence x^2= 32/50; x^2=16/25, which implies x=4/5..

francisdfreak:


Thanks a lot bro, i really appreciate.
Looks like i'll be mentioning your moniker anytime i encounter a math problem.

profmathsland:


Yes

profmathsland:



Yes

masperano:
can you solve this geometry problem for 6th grade in China.

masperano:
can you solve this geometry problem for 6th grade in China.

naturalwaves:

Area of tringle ACD = 1/2b * h
=1/2 * 20 * 10
= 100
If the 2 different parts of the circle in the down region containing the red areas are joined together, we will get a complete circle. Therefore, we need to subtract the area of the circle from the area of the triangle to get the part that remains.
The radius of the circle is 5 (i.e half way through the side of the rectangle. Hence, area = pie * radius square
= 22/7 * 25
78.57
The remaining portion of the area = 100- 78.57
=21.43
But 21.43 is not the area of the remaining red region. In order to get the area of the red region, we still need to subtract that small part down there around the place I tagged “ A ” and this is where the problem lies.
The final solution will be gotten by subtracting the area of the small region close to where I tagged "A" from 21. 43. I do not know how to get the area of that small region but if I extend the image to make a square and try and see or guess what size of the square that portion will take, I will say around 1/8 of the portion.
Area of square is 25 and 1/8 of it will give 3.125 ( this is just an estimate by eyes o. lol)
THerefore, estimated area of the red region is 21.43- 3.125 = 18.305 metre or centimeter square since you did not give the unit of the dimensions.
Note: The real answer should flabitate between plus or minus 2 from this estimated answer

masperano:


Lol nice guess.... I still believe if you look at it well you can solve it accurately without eyeballing it. Think about it more and see if you can..I will provide the solution when you demand. cheers mate

masperano:
can you solve this geometry problem for 6th grade in China.

thankyouJesus:

Area of rectangle - 2(area of circle)

you can divide the answer by 8 to get area of each corner......it should be easy from here

naturalwaves:

Okay bro. I think I will need some angle formulas to resolve that o if I wanted to and I have lost touch with most of them. I will try again sha maybe after work but I doubt if this is for 6th grade o.